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Crazy boy [7]
2 years ago
14

Quickly solve (x+7)2=121, for x. Graph the solution on a number line.

Mathematics
1 answer:
asambeis [7]2 years ago
3 0

Answer:

The value of the x is 53.5 or x=53.5

Step-by-step explanation:

Given data in the question:-      

(x+7)2=121

We have to find the value of x.

Solution:-        

(x+7)2=121\\=>2x+14=121\\=>2x=121-14\\=>2x=107\\=>x=107/2\\=>x=53.5\\

Hence the answer is 53.5

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What is the surface area of a square pyraimd that is 5.95cm long and 5.1 cm wide
nydimaria [60]
I believe that the answer to this question is 30.345 cm

4 0
3 years ago
Hiroto spends \$68 on e-books and paperback books combined. Each e-book he buys costs $5 and each paperback book he buys costs $
alina1380 [7]

The equation that can be used to model the situation regarding the e-books and paperback is 5x + 12y = 68

The following information can be gotten from the question:

Total amount spent on e-books and paperback = $68

<em>Cost</em><em> of e-book = $5 each.</em>

<em>Cost of paperback = $12 each</em>

<em>Number of</em><em> e-books</em><em> = x</em>

<em>Number of paperbacks = y</em>

Therefore, the equation that can be used to model the situation regarding the <em>e-books </em>and <em>paperback</em> will be:

= 5(x) + 12(y) = 68

5x + 12y = 68

The equation will be 5x + 12y = 68

Read related link on:

brainly.com/question/25212173

5 0
2 years ago
For what value of constant c is the function k(x) continuous at x = 0 if k =
nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x)  is continuous, we take the limit of the parameter as follows:

\mathbf{ \lim_{x \to 0^-} k(x) =  \lim_{x \to 0^+} k(x) =  0 }

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= c }

Provided that:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }

Using l'Hospital's rule:

\mathbf{\implies  \lim_{x \to 0} \ \  \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}=  \lim_{x \to 0}   sec \ x  \ tan \ x = 0}

Therefore:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}=0 }

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

#SPJ1

5 0
2 years ago
Please help ASAP need answer fast
kap26 [50]
A. 2
b. 0
c. -2
d. 0
f(x) just means that the number in the parentheses is the x-value and if it asks for f(x) it wants the y-value at that x point
5 0
3 years ago
The radius of a circular clock is 10.5 inches. Which measrement is closest to the circumference of the clock in inches
allsm [11]

Answer:

65.9734457254 or 65.97

Step-by-step explanation:

c= pi x diameter

c= pi x (10.5 x 2)

c= pi x 21

= 65.9734457254

3 0
2 years ago
Read 2 more answers
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