x+2 > 10 solves to x > 8 after we subtract 2 from both sides
So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.
Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.
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Summarizing everything, we can say...
5 is not in set A. True
5 is in set B. False
6 is in set A. False
6 is not in set B. False
8 is not in set A. True
8 is in set B. True
9 is in set A. True
9 is not in set B. False
Let's look at an example.
We'll add the fractions 1/6 and 1/8
Before we can add, the denominators must be the same.
To get the denominators to be the same, we can...
- multiply top and bottom of 1/6 by 8 to get 8/48
- multiply top and bottom of 1/8 by 6 to get 6/48
At this point, both fractions involve the denominator 48. We can add the fractions like so
8/48 + 6/48 = (8+6)/48 = 14/48
Add the numerators while keeping the denominator the same the entire time.
The last step is to reduce if possible. In this case, we can reduce. This is because 14 and 48 have the factor 2 in common. Divide each part by 2.
The fraction 14/48 reduces to 7/24
Overall, 1/6 + 1/8 = 7/24
You will have to type it into Microsoft word first, type a number or algebraic expression into a Word document. Press the "Ctrl," "Shift" and "=" keys on your keyboard to turn on the Superscript mode. Enter another number or expression signifying the exponent.
Hope this helps! :)
All the primes of 24 is 1,2,3,4,6,8,12,and 24
