Answer:
![V = \left[\begin{array}{ccc}5&-1\end{array}\right]](https://tex.z-dn.net/?f=V%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-1%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
We want to reflect this 2x1 vector on the line y = x.
To make this reflection we must use the following matrix:
![R=\left[\begin{array}{cc}0&1\\1&0\\\end{array}\right]](https://tex.z-dn.net/?f=R%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%261%5C%5C1%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Where R is known as the reflection matrix on the line x = y
Now perform the product of the vector <-1,5> x R.
![\left[\begin{array}{ccc}-1\\5\end{array}\right]x\left[\begin{array}{ccc}0&1\\1&0\end{array}\right]\\\\\\\left[\begin{array}{ccc}-1(0) +5(1)&-1(1)+5(0)\end{array}\right]\\\\\\\left[\begin{array}{ccc}5&-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%5C%5C5%5Cend%7Barray%7D%5Cright%5Dx%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%280%29%20%2B5%281%29%26-1%281%29%2B5%280%29%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-1%5Cend%7Barray%7D%5Cright%5D)
The vector matrix that represents the reflection of the vector <-1,5> across the line x = y is:
Answer:
are you sure this is high school level stuff? its 9% of 100
Step-by-step explanation:
The 400th term is 425.There are floor(√400) = 20 squares in the range 1..400, so the 400th term will be at least 420. There are floor(∛420) = 7 cubes in the range 1..400, so the 400th term may be as high as 427. However, there are
![\lfloor\sqrt[6]{427}\rfloor=2](https://tex.z-dn.net/?f=%5Clfloor%5Csqrt%5B6%5D%7B427%7D%5Crfloor%3D2)
numbers that are both squares and cubes. Consequently, the 400th term will be 427-2 =
425.
Answer:
62.8 in
Step-by-step explanation:
Circumfrence=pi x diameter
3.14 x 20=62.8
