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Lelechka [254]
3 years ago
13

If f(x) = 4x - 20, what is f(4)? O A. -4 оо O B. -12 O c. 4 O D. 16

Mathematics
2 answers:
4vir4ik [10]3 years ago
7 0

Answer:

A. - 4

Step-by-step explanation:

f(4) = 4(4) - 20 = 16 - 20 = - 4

gogolik [260]3 years ago
3 0
Answer: A

Explanation:

If f(x) = 4x - 20
Then find f(4):

To find f(4) simply replace 4 to x

f(4) = 4(4) - 20
f(4) = 16 - 20
f(4) = -4
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Virty [35]

Answer:

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Step-by-step explanation:

Use the point-slope formula y - k = m(x - h).  Substitute -2 for k and 3 for h, as well as -2 for m:

y + 4 = -2(x - 3).

4 0
3 years ago
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3 years ago
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7 0
3 years ago
Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec
expeople1 [14]

Answer:

cot x = \frac{cos x}{sin x}

cos x \frac{cos x}{sin x} + sin x

\frac{cos^2 x}{sin x} +sin x

sin^2 x + cos^2 x =1

Solving for cos^2 x we got cos^2 x =1 -sin^2 x and replacing this we got:

\frac{1-sin^2 x}{sin x} +sin x

\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x

csc x -sin x + sin x = csc x

And then the best option for this case would be:

b.csc x

Step-by-step explanation:

For this case we have the following expression given:

cos x cot x + sin x

We know from math properties that the definition for cot is cot x = \frac{cos x}{sin x}

If we use this definition we got:

cos x \frac{cos x}{sin x} + sin x

\frac{cos^2 x}{sin x} +sin x

Now we can use the following identity:

sin^2 x + cos^2 x =1

Solving for cos^2 x we got cos^2 x =1 -sin^2 x and replacing this we got:

\frac{1-sin^2 x}{sin x} +sin x

\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x

csc x -sin x + sin x = csc x

And then the best option for this case would be:

b.csc x

4 0
3 years ago
(8y²)(-3x²y²)(2/3xy⁴)<br><br> HELP PLEASEEEEEEEE
IRINA_888 [86]

Step-by-step explanation:

1 Remove parentheses.

8{y}^{2}\times -3{x}^{2}{y}^{2}\times \frac{2}{3}x{y}^{4}

8y

2

×−3x

2

y

2

×

3

2

xy

4

2 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}

b

a

×

d

c

=

bd

ac

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\frac{8{y}^{2}\times -3{x}^{2}{y}^{2}\times 2x{y}^{4}}{3}

3

8y

2

×−3x

2

y

2

×2xy

4

3 Take out the constants.

\frac{(8\times -3\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(8×−3×2)y

2

y

2

y

4

x

2

x

4 Simplify 8\times -38×−3 to -24−24.

\frac{(-24\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(−24×2)y

2

y

2

y

4

x

2

x

5 Simplify -24\times 2−24×2 to -48−48.

\frac{-48{y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

−48y

2

y

2

y

4

x

2

x

6 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

a

x

b

=x

a+b

.

\frac{-48{y}^{2+2+4}{x}^{2+1}}{3}

3

−48y

2+2+4

x

2+1

7 Simplify 2+22+2 to 44.

\frac{-48{y}^{4+4}{x}^{2+1}}{3}

3

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4+4

x

2+1

8 Simplify 4+44+4 to 88.

\frac{-48{y}^{8}{x}^{2+1}}{3}

3

−48y

8

x

2+1

9 Simplify 2+12+1 to 33.

\frac{-48{y}^{8}{x}^{3}}{3}

3

−48y

8

x

3

10 Move the negative sign to the left.

-\frac{48{y}^{8}{x}^{3}}{3}

−

3

48y

8

x

3

11 Simplify \frac{48{y}^{8}{x}^{3}}{3}

3

48y

8

x

3

to 16{y}^{8}{x}^{3}16y

8

x

3

.

-16{y}^{8}{x}^{3}

−16y

8

x

3

Done

6 0
2 years ago
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