Answer:
- r = 12.5p(32 -p)
- $16 per ticket
- $3200 maximum revenue
Step-by-step explanation:
The number of tickets sold (q) at some price p is apparently ...
q = 150 + 25(20 -p)/2 = 150 +250 -12.5p
q = 12.5(32 -p)
The revenue is the product of the price and the number of tickets sold:
r = pq
r = 12.5p(32 -p) . . . . revenue equation
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The maximum of revenue will be on the line of symmetry of this quadratic function, which is halfway between the zeros at p=0 and p=32. Revenue will be maximized when ...
p = (0 +32)/2 = 16
The theater should charge $16 per ticket.
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Maximum revenue will be found by using the above revenue function with p=16.
r = 12.5(16)(32 -16) = $3200 . . . . maximum revenue
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<em>Additional comment</em>
The number of tickets sold at $16 will be ...
q = 12.5(32 -16) = 200
It might also be noted that if there are variable costs involved, maximum revenue may not correspond to maximum profit.
Answer:
The number is 15
Step-by-step explanation:
1/3(number) + 25 = 2(number)
subtract 1/3(number) from each side
25 = 2(number) - 1/3(number)
25 = 6/3(number) - 1/3(number)
25 = 5/3(number)
multiple each side by 3/5, which is the reciprocal of 5/3
25(3/5) = number
15 = number
Answer:
A=432 B=520
Step-by-step explanation:
alright so there are 60 minutes in a hour so every 10 you get 6 so 6x6=36 per hour so 36x12 equals 432 parts
15 x 4 = 60 so 13 x 4 =52 per hour so 52 x 10 = 520