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Amiraneli [1.4K]
2 years ago
6

Johnetta simplified 7/9+ 3/8 her work is shown below. identify where she made an error

Mathematics
1 answer:
Sedbober [7]2 years ago
4 0
She made an error in the STEP 1
she shouldnt multiply the numbers
You might be interested in
Can someone please help me with this?
jok3333 [9.3K]
The first answer is 2
The Second is 8 
The third is, if the w changes then the p would change as well resulting to multiplication 


Hope this helps!!! 
6 0
2 years ago
. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar
yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are  K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

\frac{270}{455}=0.5934=59.34\%

(b)

The probability of selecting three 40-W bulbs is

\frac{4*3*2}{455}=0.0527=5.27\%

The probability of selecting three 60-W bulbs is

\frac{5*4*3}{455}=0.1318=13.18\%

The probability of selecting three 75-W bulbs is

\frac{6*5*4}{455}=0.2637=26.37\%

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

\frac{6*5*4}{455}=0.2637=26.37\%

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is \frac{9}{15}=0.6

Since there are no replacement, the probability of taking a second non 75-W bulb is now \frac{8}{14}=0.5714

Following this procedure 5 times, we find the probabilities

\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0
3 years ago
Peyton's field hockey team wins 4 games out of every 7 games played. Her team lost 9 games. How many games did Peyton's team pla
andre [41]

Answer:

Games played= 21 games

Step-by-step explanation:

Giving the following information:

Peyton's field hockey team wins 4 games out of every 7 games played.

We know that Peyton's team loses 3 games out of 7.

So if the team lost 9 games, the proportion is completed 3 times.

Games played= 3*7= 21 games

4 0
3 years ago
P P,Q and R can finish a task in 8, 10 and 12 hours respectivly.They started working together but after 3 hours, P and R left. H
zimovet [89]

Answer:

45 minutes

Step-by-step explanation:

Assume task completed in total x hours

\frac{x}{10} + \frac{3}{8} + \frac{3}{12} = 1 \\ 12x + 45 + 30 = 120 \\ 12x = 45 \\ x = \frac{15}{4} = 3 \frac{3}{4}

So q will take 45 more minutes

7 0
2 years ago
A clock has a diameter of 16 inches. Which measurement is closest to the area of the clock in square inches? 804.25 in2 50.27 in
meriva

Answer:

200.96 in2

Step-by-step explanation:

Area of a circle = nr²

n = 3.14

r = radius

the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.

A radius is half of the diameter

diameter = 2r

radius = 16 inches / 2 = 8 in

Area = 3.14 x 8² =  200.96 in²

3 0
2 years ago
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