The height of the antenna on the roof of the local building is approximately 8 meters.
The situation forms a right angle triangle.
<h3>Properties of a right angle triangle:</h3>
- One of its angles is equals to 90 degrees
- The sides of the triangles can be calculated using Pythagoras theorem.
Therefore, let's find the height of the building and the radio antenna from the eye point.
Using trigonometric ratios,
tan 40° = opposite / adjacent
tan 40° = x / 25
where
x = the height of the building and the radio antenna from the eye point.
x = 25 tan 40
x = 25 × 0.83909963117
x = 20.9774907794 meters
Let's find the height of the building from his eye point.
tan 28° = y / 25
where
y = height of the building from his eye point
y = 25 × tan 28°
y = 25 × 0.53170943166
y = 13.2927357915 meters
Height of the antenna = 20.9774907794 - 13.2927357915 = 7.68475498786
Height of the antenna ≈ 8 meters
learn more on elevation here: brainly.com/question/17582385?referrer=searchResults
Answer:
1) There are 15 in it, which means we need to find the 8th. The 8th is 6, which means the median is 6. We then need to find the other quartiles.
8/2=4, which means we need to look at the 4th,5th and 12th,13th.
The first one is FIVE, and the second is SEVEN. Therefore, the FIRST ONE.
2)113
3)37
Answer:
a = -29
Step-by-step explanation:
1st step is to multiply -2 on both sides
I am not sure if it is the best but heres one way to do it
