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Natasha_Volkova [10]
3 years ago
5

If A ⊂ B, then which of the following describes the relationship between A and B?

Mathematics
1 answer:
Nataliya [291]3 years ago
6 0

The answer is 4 alone, or 1 and 4, depending on how you interpret the symbol (see below for explanation).

The writing A \subset B means that A is a subset of B. This means that every element of A is also an element of B, while there are elements of B that are not elments of A. For example, even numbers are a subset of natural numbers: all even numbers are natural numbers, but not all natural numbers are even.

In theory, a subset could "fill" the whole superset (and thus they are the same set), but this is indicated by the writing A \subseteq B. Nevetheless, sometimes the two symbols are interchanged, and one writes A \subset B but means A \subseteq B.

You can think of this as the same difference between  x and x \leq y

So, the first point is false if you mean that A is a "strict" subset of B, while it can be true if you mean that A is generally a subset of B.

As for the second point, set B can't have less elements than set A. In this case, there would be an element in A not belonging to B, which is impossibile because B is a superset of A.

Third point: the intersection can't be the empty set (unless A is empty), because every element in A also belongs to be, and so the intersection between A and B is actually A itself.

Finally, the fourth point is true: basing on everything we said so far, B contains at least all the elements in A, and possibly some more.

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A man hits a baseball when it is 4 ft above the ground with an initial velocity of 120 ft/sec. The ball leaves the bat at a 30 d
Sauron [17]
<span>et us assume that the origin is the floor right below the 30 ft. fence

To work this one out, we'll start with acceleration and integrate our way up to position.

At the time that the player hits the ball, the only force in action is gravity where: a = g (vector)
ax = 0
ay = -g (let's assume that g = 32.8 ft/s^2. If you use a different value for gravity, change the numbers.

To get the velocity of the ball, we integrate the acceleration
vx = v0x = v0cos30 = 103.92
vy = -gt + v0y = -32.8t + v0sin40 = -32.8t + 60

To get the positioning, we integrate the speed.
x = v0cos30t + x0 = 103.92t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + 60t + 4

If the ball clears the fence, it means x = 0, y > 30

x = 0 -> 103.92 t - 350 = 0 -> t = 3.36 seconds

for t = 3.36s,
y = -16.4(3.36)^2 + 60*(3.36) + 4
= 20.45 ft

which is less than 30ft, so it means that the ball will NOT clear the fence.


Just for fun, let's check what the speed should have been :)

x = v0cos30t + x0 = v0cos30t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + v0sin30t + 4

x = 0 -> v0t = 350/cos30
y = 30 ->
-16.4t^2 + v0t(sin30) + 4 = 30
-16.4t^2 + 350sin30/cos30 = 26
t^2 = (26 - 350tan30)/-16.4
t = 3.2s

v0t = 350/cos30 -> v0 = 350/tcos30 = 123.34 ft/s

So he needed to hit the ball at at least 123.34 ft/s to clear the fence.

You're welcome, Thanks please :)
</span>
6 0
3 years ago
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