15 points

2 answers:

6 0

In this exercise is given that a triangle has a vertex R at the coordinate (-4,1) and it is says that this point was rotated 90 degrees counterclockwise from the origin. It is asked to find the rotation which is equivalent to 90 degree counterclockwise rotation.

First of all a 90 degree counterclockwise rotation is define by the rule
(x,y)--(-y,x), which means that every time a 90 degree counterclockwise rotation occurs the given point has to be changed according to the previous mention rule.

In the other hand, a 90 degree clockwise rotation is define by the rule (x,y)--(y,-x). A 360 degree counterclockwise rotation is define by (x,y)--(x,y), and a 270 degree clockwise rotation is represented by the rule (x,y)--(-y,x).

By the previous said, the rotation which is equivalent to a 90 degree counterclockwise rotation is a 270 degree clockwise rotation.

melisa1 [442]2 years ago

5 0

Clockwise 270 degrees is the answer

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Hey can you please help me posted picture of question

Arte-miy333 [17]

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Explanation:

All the other options are theoretical probabilities because they were determined using the equation:

probablity = number of positive events / total number of possible events.

While, experimental probabilities are determined from actual results of an experiment (test). That is what the option C. describes. It compares the number of times that she actually got a message (5) with the number of trials (12). It is not determined theoretically.

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yawa3891 [41]

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Step-by-step explanation:

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nalin [4]

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aleksley [76]

Considering that the subjects are chosen without replacement, they are not independent, and the probability cannot be found using the binomial distribution.

The binomial distribution and the hypergeometric distribution are quite similar, as:

They find the probability of exactly x successes on n repeated trials.
For each trial, there are only two possible outcomes.

The difference is that the binomial distribution is for independent trials, that is, in each trial, the probability of success is the same, while the hypergeometric distribution is for dependent trials.