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3 years ago

. Gabby received six job offers from the 15 interviews he did last month. Which ratio best

Mathematics

1 answer:

gavmur [86]3 years ago

7 0

Answer:

The ratio that describes the relationship between number of jobs not offered and the number of jobs interviewed is $\frac{3}{5}$ .

Step-by-step explanation:

The following can be calculated from the given question;

Number of job offered = 6

Number of job interviewed = 15

Number of jobs not offered = 15 - 6

= 9

The ratio between jobs not offered and the number of jobs interviewed is;

= $\frac{jobs not offered}{jobs interviewed}$

= $\frac{9}{15}$

= $\frac{3}{5}$

The ratio that describes the required relationship between jobs not offered and jobs interviewed is $\frac{3}{5}$ .

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Elan Coil [88]

The formula is
A=p (1+r)^t
A future value?
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R rate of inflation 0.034
T time 2008-2005=3 years
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A=155

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3 years ago

MZRSK = x + 53, m KST = x + 109,<br> and mZRST = 156º<br><br><br> Find x.

Dahasolnce [82]

Answer:

$-3 = x$

Step-by-step explanation:

Since we are not given a midpoint, we use the Angle Addition Postulate:

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[−3 + 53] + [−3 + 109] = 156

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156 = 156 ☑

Therefore, $-3 = x$ is a genuine statement.

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3 years ago

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IRINA_888 [86]

The area of rhombus is 24 square units.

Step-by-step explanation:

Given,

Length of one diagonal = p = 3+3 = 6 units

Length of other diagonal = q = 4+4 = 8 units

Area of rhombus = $\frac{pq}{2}$

Area of rhombus = $\frac{6*8}{2}$

Area of rhombus = $\frac{48}{2}$

Area of rhombus = 24 square units

The area of rhombus is 24 square units.

Keywords: rhombus, area

Learn more about areas at:

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Answer with explanation:

The given statement is which we have to prove by the principal of Mathematical Induction

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1.→For, n=1

L H S =2

R H S=1

2>1

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2.⇒Let the statement is true for, n=k.

$2^{k}>k$

---------------------------------------(1)

3⇒Now, we will prove that the mathematical statement is true for, n=k+1.

$\rightarrow 2^{k+1}>k+1\\\\L H S=\rightarrow 2^{k+1}=2^{k}\times 2\\\\\text{Using 1}\\\\2^{k}>k\\\\\text{Multiplying both sides by 2}\\\\2^{k+1}>2k\\\\As, 2 k=k+k,\text{Which will be always greater than }k+1.\\\\\rightarrow 2 k>k+1\\\\\rightarrow2^{k+1}>k+1$

Hence it is true for, n=k+1.

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mrs_skeptik [129]

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