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Vinil7 [7]
3 years ago
5

5y/1 / 1/3 = y−0.9/0.2 Please solve this to find y!

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
8 0

The answer is y= -1.63:

Leona [35]3 years ago
3 0
The answer is going to be Y 1.63
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Please help me with 12!
Liono4ka [1.6K]
Four different colours I believe. Because it says each ticket type will be a different colour. Therefor, adult (1), child (2), 1-day (3), 2-day (4).

Hope this was helpful and correct! 

 
3 0
2 years ago
Read 2 more answers
) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle
Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

x=0,y=2\implies z=-2\implies(0,2,-2)

x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to S to be

\vec s_v\times\vec s_u=(20v,8v,4v)

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv

=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}

8 0
3 years ago
Please help me I just kinda got stuck on this one Thank you so much
Anika [276]
C 90 inches squared i took this same one
4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%288%20%2B%204%20%2B%203%29%20%2B%20%286%20%2B%205%20%2B%2011%29%20%3D%20" id="TexFormula1" ti
marta [7]

Answer:

= 37

Step-by-step explanation:

(8+4+3) + (6+5+11)

= 15 + 22

= 37

3 0
3 years ago
Quadrilateral JKLM is a rhombus. The diagonals intersect at N. If angle JNK equals 5x - 15, find the value of x.
VLD [36.1K]
One property of a rhombus is that the diagonals are perpendicular. This means that the diagonals intersect at 90 degree angles (right angles).

So we know that angle JNK is 90 degrees

angle JNK = 90 degrees
5x - 15 = 90
5x - 15 + 15 = 90+15
5x = 105
5x/5 = 105/5
x = 21

Answer: x = 21
3 0
3 years ago
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