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FinnZ [79.3K]
2 years ago
15

Given: Prove: Proof: Question 14 of 24 What is the missing reason in the proof? segment addition Congruent Segments Theorem Tran

sitive Property of Equality Subtraction Property of Equality
Mathematics
1 answer:
Paha777 [63]2 years ago
4 0
The answer is Segment Addition Congruent
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Hey can you please help me posted picture of question :)
andriy [413]
The answer is the answer is C and F.

This is found by inserting the equation above into the quadratic formula or -b plus or minus the square root of b^2 - 4ac over 2a.

With that, you find that the first number is a -3, which eliminates choices B and D.

Then, solving the 4ac portion, you find that inside the square root the number is 29, which gives you the last two answer choices.

Hope this helps!
5 0
3 years ago
If each side of a square grows 6 mm, the area of ​​the square is multiplied by 16. How long are the sides of the original square
Phoenix [80]

Answer:

2 mm

Step-by-step explanation:

Let x be the sides of the original square,

then the area of the original square is x^2

The sides of the new square is x + 6

The area is (x + 6)^2

Then (x + 6)^2 = 16*x^2

Take square root on both sides and get

x + 6 = 4x,

3x = 6

so x = 2 mm

3 0
2 years ago
What capital leffer appears to have parallel lines?<br><br><br><br> D or L or N or T?
Liono4ka [1.6K]

Answer:

N, the verticle lines are are parallel

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Select all the conditions for which it is possible to construct a triangle. (7.G.1.2) Group of answer choices a. A triangle with
saw5 [17]

Answer:

  b, d, e, f

Step-by-step explanation:

Here are the applicable restrictions:

  • The sum of angles in a triangle is 180°, no more, no less.
  • The sum of the lengths of the two shortest sides exceeds the longest side.
  • When two sides and the angle opposite the shortest is given, the sine of the given angle must be at most the ratio of the shortest to longest sides.

a. A triangle with angle measures 60°, 80°, and 80° (angle sum ≠ 180°, not OK)

b. A triangle with side lengths 4 cm, 5 cm, and 6 cm (4+5 > 6, OK)

c. A triangle with side lengths 4 cm, 5 cm, and 15 cm (4+5 < 15, not OK)

d. A triangle with side lengths 4 cm, 5 cm, and a 50° angle across from the 4 cm side (sin(50°) ≈ 0.766 < 4/5, OK)

e. A triangle with angle measures 30° and 60°, and an included 3 cm side length (OK)

f. A triangle with angle measures 60°, 20°, and 100° (angle sum = 180°, OK)

_____

<em>Additional comment</em>

In choice "e", two angles and the side between them are specified. As long as the sum of the two angles is less than 180°, a triangle can be formed. The length of the side is immaterial with respect to whether a triangle can be made.

__

The congruence postulates for triangles are ...

  SSS, SAS, ASA, AAS, and HL

These essentially tell you the side and angle specifications necessary to define <em>a singular triangle</em>. As we discussed above, the triangle inequality puts limits on the side lengths specified in SSS. The angle sum theorem puts limits on the angles when only two are specified (ASA, AAS).

In terms of sides and angles, the HL postulate is equivalent to an SSA theorem, where the angle is 90°. In that case, the angle is opposite the longest side (H). In general, SSA will specify a singular triangle when the angle is opposite the <em>longest</em> specified side, regardless of that angle's measure. However, when the angle is opposite the <em>shortest</em> specified side, the above-described ratio restriction holds. If the sine of the angle is <em>less than</em> the ratio of sides, then <em>two possible triangles are specified</em>.

4 0
2 years ago
A magazine publisher mails a survey to every subscriber asking about the quality of its subscription service.
scoray [572]
A Statistic.

Since they want to know how their magazine are, they are gonna make a survey. In the survey, the people are statistics to see how well their magazines are. With that, they can decide to change their subjects or whatever it is. Hope this helps!
3 0
3 years ago
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