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3 years ago

15

Given: Prove: Proof: Question 14 of 24 What is the missing reason in the proof? segment addition Congruent Segments Theorem Tran

sitive Property of Equality Subtraction Property of Equality

1 answer:

Paha777 [63]3 years ago

4 0

The answer is Segment Addition Congruent

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Factorise this expression as fully as possible<br>4x²+x

borishaifa [10]

You can only factor $x$ out of both terms:

$x(4x+1)$

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3 years ago

Which relation is not a function

3241004551 [841]

Answer:

B

Step-by-step explanation:

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2 years ago

The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as mc024-1.j

Alex Ar [27]

We have the given I = 10^-1 and I₀ = 10^-12.

Simply plugging in the values to the equation, we have:
L = 10log(10^-1/10^-12)
L = 110 Db

The answer is D.

(I used a scientific calculator in solving for L).

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3 years ago

Read 2 more answers

Find the solution by graphing the equations pls help

lilavasa [31]

Answer:

graph these
y = 2x + 2
y = 2x - 3

Step-by-step explanation:

2x - y = -2
2x - y = 3

convert to y intercept form
first
2x - y = -2
-y = -2x - 2
y = 2x + 2
second
2x - y = 3
-y = -2x + 3
y = 2x - 3

you are left with
y = 2x + 2
y = 2x - 3
i cannot graph these for you, but i assume you know how, there is no solution because the lines are parallel

4 0

2 years ago

The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m

rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}$

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}$

$\text{Fuel used by 1st auto}=30 \text{ gallons}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}$

$\text{Fuel used by 2nd auto}=20 \text{ gallons}$

Let us find the difference of fuel used by both autos.

$\text{Number of gallons that 2nd auto used less than 1st auto}=30-20$

$\text{Number of gallons that 2nd auto used less than 1st auto}=10$

Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces $5\times 10=50$ pounds of carbon.

Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

8 0

3 years ago