With a given parallel line and a given point on the line
we can use the point-line method: y-y0=m(x-x0)
where
y=mx+k is the given line, and
(x0,y0) is the given point.
Here
m=-10, k=-5, (x0,y0)=(-3,5)
=> the required line L is given by:
L: y-5=-10(x-(-3))
on simplification
L: y=-10x-30+5
L: y=-10x-25
Answer:
=
10
−
2
7
-
3
Step-by-step explanation:
Answer:
The diameter is 24 so the radius is 12 then we do pi*r^2 or pi*12^2
We can use our numbers and get pi*144 so the area of the circle is 144pi.
If they have given you what pi is
EX:( 22/7 or 3.14)
Just use that instead of pi and multiply 144 to that
PQRS is a parallelogram Given
SR=PQ property of parallelogram
m∠S=m∠Q property of parallelogram
SP=QR property of parallelogram
XP=RY given
SP-XP=QR-RY substitution
SX=QY segment subtraction
ΔSRX is conggruent to ΔQPY SAS theorem (side-angle-side)
XR=YP CPCTC (corresponding parts of congruent triangles are congruent)
Answer:
the answer is 5... 5- (-10) and 6-3 and divide the change by 15 and 3 and you'll get 5
Step-by-step explanation:
