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kvasek [131]
3 years ago
14

-412-(-223) worked out

Mathematics
2 answers:
shutvik [7]3 years ago
5 0

Answer:

-189

Step-by-step explanation:

Remember to follow the rules of signs:

- If there are two positive signs next to each other, you add:

- If there is one negative sign and one positive sign next to each other, you subtract.

- If there is two negative signs next to each other, you add:

- 412 - (-223) = -412 + 223

Subtract:

223 - 412 = -189

-189 is your answer.

~

vaieri [72.5K]3 years ago
3 0
This is the answer to the question -189
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What is x ? please help :)
bekas [8.4K]

Answer:

x =12

Step-by-step explanation:

The two angles are complementary, so the add to 90 degrees

5x+1/2x +24 = 90

Combine like terms

5 1/2 x +24 = 90

Subtract 24 from each side

5 1/2 x = 90-24

Change the mixed number to an improper fraction

11/2 x = 66

Multiply by the reciprocal 2/11 on each side

2/11 *11/2 x = 66*2/11

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4 years ago
Bob's age is 4 times greater than Susanne's age. Dakota is three years younger than Susanne. The sum of Bob's, Susanne's, and Da
Ratling [72]
<span>Susanne is 16 years old.</span>

b = Bob's age

s = Susanne's age

d = Dakota's age

Bob's age is 4 times greater than Susanne's age:

b = 4s

Dakota is three years younger than Susanne:

d = s - 3

The sum of Bob's, Susanne's, and Dakota's ages is 93:

b + s + d = 93


 solve these equations:

b = 4s

d = s - 3

b + s + d = 93


and get:

b = 64 years

s = 16 years

(remember that s = Susanne)

d = 13 years
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3 years ago
PLEASE ANSWER!!!!WILL MARK BRAINLIEST!!!
Setler79 [48]
Hope this is helpful

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Complete the point slope equation of the lone through (-8,-1) and (-6,5)​
sweet-ann [11.9K]

Answer:

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3 years ago
X2 - 6x + 12 and y = 2x - 4, algebraically are
olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x^2 - 6x + 12 = 2x - 4

Make the right side of equation 0

x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0

<em><u>Solve by quadratic equation</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4

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y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

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3 years ago
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