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galina1969 [7]
3 years ago
13

solve the following systems of equations. Express your answer as an ordered pair in the format(a,b), with no spaces between the

number symbols. 2x+7y=-7. -4x-3y=-19
Mathematics
1 answer:
kodGreya [7K]3 years ago
7 0
If you multiply the top equation by -2 you get:

-4x -14y = 14 => -4x = 14+14y

now you can plug in the -4x into the second equation:

 14+14y - 3y = -19 => 11y = -33 => y=-3

Fill in y=-3 in either equation to find x:

2x - 21 = -7 => 2x = 14 => x=7

So your ordered pair is (7,-3)
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Please help me with the below question.
VMariaS [17]

By letting

y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}

we get derivatives

y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}

y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0

Examine the lowest degree term \left(x^{r-1}\right), which gives rise to the indicial equation,

5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients c_k is

(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}

so that with r = 4/5, the coefficients are governed by

c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}

c) Starting with c_0=1, we find

c_1 = -\dfrac{c_0}5 = -\dfrac15

c_2 = -\dfrac{c_1}{10} = \dfrac1{50}

so that the first three terms of the solution are

\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}

4 0
2 years ago
Please write a equation for this table
Hitman42 [59]

Answer:

  y = 5x +2

Step-by-step explanation:

The point (0, 2) tells us the y-intercept is 2.

If we translate the table down 2 units by subtracting 2 from every y-value, it becomes ...

  6, 30

  -2, -10

  0, 0

  10, 50

We notice these values are all related by a factor of 5 (they are proportional). That means the equation will be a straight line with slope 5 and y-intercept 2.

  y = 5x +2

6 0
2 years ago
Determine m∠BIH. (please help)
noname [10]

Answer: BIH it seems like u need some hw help bud! ur not getting it tho

Step-by-step explanation:

8 0
2 years ago
Pls answer if you only know the correct answer! Thanks! :)
Aleonysh [2.5K]

Answer:

I would say it's -0.8

Step-by-step explanation:

Since 3 is pretty far, I'm assuming -2 is at the left end of the line, so -.8 seems like the most reasonable answer.

4 0
3 years ago
Read 2 more answers
The owner of a football team claims that the average attendance at games is over 523, and he is therefore justified in moving th
USPshnik [31]

Answer:

C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.

Step-by-step explanation:

Let μ be the the average attendance at games of the football team

The claim: the average attendance at games is over 523

Null and alternative hypotheses are:

  • H_{0}: μ=523
  • H_{a}: μ>523

The conclusion is failure to reject the null hypothesis.

This means that <em>test statistic</em> is lower than <em>critical value</em>.  Therefore it is not significant, there is no significant evidence to accept the <em>alternative</em> hypothesis.

That is no significant evidence that the average attendance at games of the football team is greater than 523.

7 0
2 years ago
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