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2 years ago

Eight times a number increased by 6 is 62

Mathematics

2 answers:

qaws [65]2 years ago

8 0

8x+6=62
8x=56
X=56/8
X=7

N76 [4]2 years ago

3 0

8x+6=62

8x=62-6

8x=56

X=56/8

X=7

The answer is 7. Hope this helps!

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What is the center of the circle that has a diameter whose endpoints are (9, 7) and (-3, -5)?

emmasim [6.3K]

Answer: OPTION B.

Step-by-step explanation:

Given the endpoints of the diameter of the circle, we need to find the midpoint, which is the center of the circle.

The following formula is used to calculate the Midpoint:

$M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Given the endpoints of the diameter of the circle:

$(9, 7)\ and\ (-3, -5)$

We can identify that:

$x_1=9\\x_2=-3\\y_1=7\\y_2=-5$

Then, we can substitute these values into the formula:

$M=(\frac{9+(-3)}{2},\frac{7+(-5)}{2})\\\\M=(3,1)$

Therefore, the center of the circle is: $(3,1)$

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3 years ago

What is greater 95% or 1 1/2

Snowcat [4.5K]

1 1/2 cause your getting half not just sum

4 0

3 years ago

5. Point A is 3 units directly below (2, 2). What are the coordinates of point A? Answer: Point A (___)

fiasKO [112]

A is (2, -1)

The X axis will not change since A is not going left or right of (2,2). You would count down 3 spaces for the y-axis and that would land you at -1 or you could solve by subtraction.

2-3= -1

3 0

8 months ago

7/8y + 1/2 = 1 1/5 Solve for y.

abruzzese [7]

Answer:

y = 4/5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify

7/8y + 1/2 = 1 1/5

Step 2: Solve for y

Convert to improper fraction: 7/8y + 1/2 = 6/5
[Subtraction Property of Equality] Subtract 1/2 on both sides: 7/8y = 7/10
[Division Property of Equality] Divide 7/8 on both sides: y = 4/5

3 0

2 years ago

Find the f^-1(x) and it’s domain

borishaifa [10]

Answer:

$f^{-1}(x) = (x + 8)^2$

$x \ge -8$

Step-by-step explanation:

Given

$f(x) = \sqrt x - 8$

Solving (a): $f^{-1}(x)$

We have:

$f(x) = \sqrt x - 8$

Express f(x) as y

$y = \sqrt x - 8$

Swap x and y

$x = \sqrt y - 8$

Add 8 to $both\ sides$

$x + 8 = \sqrt y - 8 + 8$

$x + 8 = \sqrt y$

Square both sides

$(x + 8)^2 = y$

Rewrite as:

$y = (x + 8)^2$

Express y as: $f^{-1}(x)$

$f^{-1}(x) = (x + 8)^2$

To determine the domain, we have:

The original function is $f(x) = \sqrt x - 8$

The range of this is: $f(x) \ge -8$

The $domain$ of the $inverse$ function is the $range$ of the $original$ function.

Hence, the domain is:

$x \ge -8$

3 0

3 years ago