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denis23 [38]
3 years ago
6

What is the shortest possible distance between the houses

Mathematics
2 answers:
Iteru [2.4K]3 years ago
7 0

Answer: 17 easy how could you not get it but yea thats that

Step-by-step explanation:

MatroZZZ [7]3 years ago
3 0

Answer:

A.) 8.5 miles

Step-by-step explanation:

I think its a because it says "<u><em>THE SHORTEST possible</em></u>" distance between the houses. So A.) 8.5 miles is the correct answer because A.)8 .5 miles is the shortest answer in the list of answers.

Hope this helped.

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Given f(x) = –3x – 7, what is f(–4)?
lyudmila [28]
The answer is D hope this help

8 0
3 years ago
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A class of 118 students went on a field trip. They took 10 vehicles, some vans (x) and some buses (y). Find the number of vans a
I am Lyosha [343]

Answer:

Solve for x+y=10

               6x+35y=118

Step-by-step explanation:

I would solve it for you but my calculator isn't working rn. You could also use a picture calculator and it will give you a more in depth explanation. Hope this helps!

7 0
3 years ago
If you can please do it all just tryna go to sleep
Lubov Fominskaja [6]

Answer:

1. 1

2. -3

3. yes

4. no, it is not, because the function stop at point (-6, -2)

5. -2

6 0
2 years ago
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
2 years ago
Find a quadratic expression with integer coefficients whose roots are <img src="https://tex.z-dn.net/?f=5%2F2%2B%203i" id="TexFo
prohojiy [21]

Answer:

4x² -20x  +61

Step-by-step explanation:

the quadratic equation can be written as (x-root1)(x-root2)

(x-(5/2) -3i) (x-(5/2)+3i), distribute

x² -(5/2)x +3xi -(5/2)x + 25/4 -(15/2)i -3xi +(15/2)i -9i², simplify

x² -(5/2)x -(5/2)x + 25/4  -9i², use the fact that i² =(√-1)² = -1 and substitute i²

x² -(5/2)x -(5/2)x + 25/4 +9, combine like terms and rewrite 9 as 36/4

x² -(10/2)x  +25/4 + 36/4, combine like terms and simplify

x² -5x  +61/4 is the quadratic expression yet it does not have integer coefficients so multiply by 4 to have all coefficients integers

4x² -20x  +61

7 0
3 years ago
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