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iVinArrow [24]
3 years ago
16

The estimated total cost, y, of a child’s toy is partially based on the number of batteries used, x. The cost of one battery is

$0.75. The toy itself costs $12. Which equation represents the situationThe estimated total cost, y, of a child’s toy is partially based on the number of batteries used, x. The cost of one battery is $0.75. The toy itself costs $12. Which equation represents the situationThe estimated total cost, y, of a child’s toy is partially based on the number of batteries used, x. The cost of one battery is $0.75. The toy itself costs $12. Which equation represents the situationThe estimated total cost, y, of a child’s toy is partially based on the number of batteries used, x. The cost of one battery is $0.75. The toy itself costs $12. Which equation represents the situation?
A: y=12x+0.75
B: y=0.75x-0.75
C: y=12x-0.75
D: y=0.75x-12
Mathematics
2 answers:
frozen [14]3 years ago
9 0

Answer:

SHE OR HE MEANS B.)

Step-by-step explanation:

B.)

mixas84 [53]3 years ago
6 0

Answer: The equation that represents the give situation is, y = 0.75 x + 12

Step-by-step explanation:

Here, x represents the number of batteries the child bought and y represents the total cost.

Since, the cost of one batteries = $ 0.75

⇒ The cost of x batteries = 0.75 x

The cost of one toy = $ 12

Hence, the total cost = The cost of one toy + The cost of x batteries

= y = 0.75 x + 12

Which is the required equation that represents the given situation.

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Answer:

\large\boxed{x=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

Step-by-step explanation:

16y^2-25=0\\\\METHOD\ 1:\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\16=4^2\ \text{and}\ 25=5^2\ \text{therefore we have}\\\\4^2y^2-5^2=0\\\\(4y)^2-5^2=0\\\\(4y-5)(4y+5)+0\iff4y-5=0\ \vee\ 4y+5=0\\\\4y-5=0\qquad\text{add 5 to both sides}\\4y=5\qquad\text{divide both sides by 4}\\\boxed{y=\dfrac{5}{4}}\\\\4y+5=0\qquad\text{subtract 5 from both sides}\\4y=-5\qquad\text{divide both sides by 4}\\\boxed{x=-\dfrac{5}{4}}

METHOD\ 2:\\\\16y^2-25=0\qquad\text{add 25 to both sides}\\\\16y^2=25\qquad\text{divide both sides by 16}\\\\y^2=\dfrac{25}{16}\to y=\pm\sqrt{\dfrac{25}{26}}\\\\y=-\dfrac{\sqrt{25}}{\sqrt{16}}\ \vee\ x=\dfrac{\sqrt{25}}{\sqrt{16}}\\\\\boxed{y=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

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3 years ago
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Each day the 29 people in Ms.Gills band class play music for 34 minutes.what would be the best estimate for the amount of music
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234 bc you they play 34 mins in one day and just times 34 by 7 and it will get ur answer.

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Im so confused with algebraic expressions I'm struggling a lot
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Please helpppp....????​
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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

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<u>Geometry</u>

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Step-by-step explanation:

<u>Step 1: Set up Equation</u>

x + (x + 65) + 25 = 180

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Combine like terms:                     2x + 90 = 180
  2. Isolate <em>x</em> term:                               2x = 90
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8 0
3 years ago
A chemist has two acid solutions in stock: one is a 50% solution, and the other is a 80% solution. How much of each solution sho
arsen [322]
Easy way, visual

                    50---68---80%
Difference        18    12
Invert order to give ratio of 50% and 80%
Ratio                12    18 = 2:3

So by simple proportion:
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volume of 80% needed = 100*3/(2+3)=60 mL

Algebra way
Let x=volume of 50% needed.
Then
0.50*x+0.80*(100-x) = 0.68(100)
Expand and solve for x
0.5x+80-0.8x = 68
0.8x-0.5x = 80-68
0.3x = 12
x=12/0.3 = 40 mL (volume of 50%)
100-x=100-40=60 mL (volume of 80%)

8 0
3 years ago
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