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2 years ago

8

Find the sum of 5 9/13 + 5 9/13

2 answers:

NNADVOKAT [17]2 years ago

7 0

Answer: 148/13 or (5 9/13) + (5 9/13) = 11.3846153846

Simplify the following:

5 + 9/13 + 5 + 9/13

Put 5 + 9/13 + 5 + 9/13 over the common denominator 13. 5 + 9/13 + 5 + 9/13 = (13×5)/13 + 9/13 + (13×5)/13 + 9/13:

(13×5)/13 + 9/13 + (13×5)/13 + 9/13

13×5 = 65:

65/13 + 9/13 + (13×5)/13 + 9/13

13×5 = 65:

65/13 + 9/13 + 65/13 + 9/13

65/13 + 9/13 + 65/13 + 9/13 = (65 + 9 + 65 + 9)/13:

(65 + 9 + 65 + 9)/13

| 2 |

| 6 | 5

| 6 | 5

| | 9

+ | | 9

1 | 4 | 8:

Answer: 148/13

matrenka [14]2 years ago

5 0

You have to add those two together, so your problem would look like this:

5 (your whole mumber)

9/13 (your fraction)

5 9/13 + 5 9/13 = 10 - the whole number

9/13 + 9/13 = 18/13 since the denomentator always stays the same! (the bottom half) so, we have to make 18/13 a proper fraction since its mixed right now. To do that, we need to subtract the numerator (the top) and the denomentator to see how many times 13 can go into 18. So what you do is 18-13 and you get 5 left. It only went in once, so you would add to your whole number you had previously which was 10. You get 11, and since you had left your fraction would look like 5/13.

Therefore, your answer would be 11 5/13.

Hope this helped!

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Let h(x)=20e^kx where k ɛ R (Picture attached. Thank you so much!)

zloy xaker [14]

Answer:

A)

$k=0$

B)

$\displaystyle \begin{aligned} 2k + 1& = 2\ln 20 + 1 \\ &\approx 2.3863\end{aligned}$

C)

$\displaystyle \begin{aligned} k - 3&= \ln \frac{1}{2} - 3 \\ &\approx-3.6931 \end{aligned}$

Step-by-step explanation:

We are given the function:

$\displaystyle h(x) = 20e^{kx} \text{ where } k \in \mathbb{R}$

A)

Given that h(1) = 20, we want to find <em>k</em>.

h(1) = 20 means that <em>h</em>(x) = 20 when <em>x</em> = 1. Substitute:

$\displaystyle (20) = 20e^{k(1)}$

Simplify:

$1= e^k$

Anything raised to zero (except for zero) is one. Therefore:

$k=0$

B)

Given that h(1) = 40, we want to find 2<em>k</em> + 1.

Likewise, this means that <em>h</em>(x) = 40 when <em>x</em> = 1. Substitute:

$\displaystyle (40) = 20e^{k(1)}$

Simplify:

$\displaystyle 2 = e^{k}$

We can take the natural log of both sides:

$\displaystyle \ln 2 = \underbrace{k\ln e}_{\ln a^b = b\ln a}$

By definition, ln(e) = 1. Hence:

$\displaystyle k = \ln 2$

Therefore:

$2k+1 = 2\ln 2+ 1 \approx 2.3863$

C)

Given that h(1) = 10, we want to find <em>k</em> - 3.

Again, this meas that <em>h</em>(x) = 10 when <em>x</em> = 1. Substitute:

$\displaystyle (10) = 20e^{k(1)}$

Simplfy:

$\displaystyle \frac{1}{2} = e^k$

Take the natural log of both sides:

$\displaystyle \ln \frac{1}{2} = k\ln e$

Therefore:

$\displaystyle k = \ln \frac{1}{2}$

Therefore:

$\displaystyle k - 3 = \ln\frac{1}{2} - 3\approx-3.6931$

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2 years ago

List the square numbers less than 90 and greater than 50

Setler79 [48]

$7^2=49 \ \textless \ 50-NOT\\8^2=64-YES\\9^2=81-YES\\10^2=100 \ \textgreater \ 90-NOT$

5 0

3 years ago

Recall the formula for the area of a trapezoid, A=1/2h(a+b) , where h is the height and a and b are the lengths of the parallel

Gekata [30.6K]

Answer:

The area of the trapezoid is 40 square inches

Step-by-step explanation:

Here, we want to find the area of the given trapezoid

Mathematically, we apply the formula for the area

In this case, a will be 10, b will be 6 and h will be 5

Substituting these values, we have that ;

A = 1/2(10 + 6)5

A = 1/2(16)(5)

A = 40 square inches

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Donald's car gets about 30 miles per gallon. About how many miles can Donald drive on 9.2 gallons of gas? At $3.15 a gallon, abo

denis-greek [22]

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2 years ago

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mario62 [17]

Answer:

see attached

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2 years ago