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likoan [24]
3 years ago
5

Find the volume (in terms of pi) of a sphere of its surface area is 400 pi ft2

Mathematics
2 answers:
elixir [45]3 years ago
8 0

\bf \textit{surface area of a sphere}\\\\ SA=4\pi r^2\qquad \qquad \implies \stackrel{SA}{400\pi }=4\pi r^2\implies \cfrac{400\pi }{4\pi }=r^2 \\\\\\ 100=r^2\implies \sqrt{100}=r\implies \boxed{10=r} \\\\\\ \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}\qquad \qquad V=\cfrac{4\pi \boxed{10^3}}{3}\implies V=\cfrac{4000\pi }{3}

Rama09 [41]3 years ago
7 0

Answer: 1333.33\pi\ ft.^3

Step-by-step explanation:

The surface area of sphere is given by :-

S.A=4\pi r^2, where r is radius of sphere.

Given : Surface area of sphere =400 \pi \ft2

\\\Rightarrow 400 \pi =4\pi r^2\\\\\Rightarrow\ r^2=\dfrac{400}{4}=100\text{ ft.}

The volume of sphere is given by :-

V=\dfrac{4}{3}\pi r^3\\\\\Rightarrow\ V=\dfrac{4}{3}\pi (100)^3\\\\\Rightarrow\ V=\dfrac{4000}{3}\pi=1333.33333\approx1333.33\pi\ ft.^3

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denis-greek [22]

Answer:

(a) 0.85

(b) 0.7225

Step-by-step explanation:

(a) The point estimate for the proportion of all such components that are not defective is given by the number of non-defective units in the sample divided by the sample size:

p=\frac{80-12}{80}\\p=0.85

The proportion is 0.85.

(b) Assuming that the sample is large enough to accurately provide a point estimate for the whole population, this can be treated as a binomial model with probability of success (non-defective part) p = 0.85. Since both components must be non-defective for the system to work, the probability of two successes in two trials is:

P(x=2) = 0.85^2\\P(x=2) = 0.7225

An estimate of 0.7225 for the proportion of all such systems that will function properly.

4 0
3 years ago
Write 0.008 as a percentage.
Readme [11.4K]

Answer:

.8%

Step-by-step explanation:

Percent means out of hundred meaning that 8% = 0.08 so .8% = 0.008

5 0
3 years ago
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A bag contains 12 pennies, 9 nickels, 11 dimes and 3 quarters. A coin is selected at random from the bag. Find the probability.
steposvetlana [31]
Probablity=desiredoutcomes/totalpossibleoutcomes

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6 0
4 years ago
Suppose we roll a fair six-sided die 20 times and draw ten cards from a standard 52-card deck. Let X be the number of "6"s rolle
Lera25 [3.4K]

Answer:

a) Expected value = 6.406

Variance = 4.905

Standard deviation = 2.45

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Step-by-step explanation:

a) Let's suppose that:

X₁ = number of 6´s

X₂ = number of Jack, Queen, King or Aces

The mean of X₁ is:

MeanX₁ = n * p = 20 * (1/6) = 3.33

The variance of X₁ is:

Var-X_{1} =np(1-p)=3.33(1-(1/6))=2.775

The mean of X₂ is:

MeanX₂ = 10 * (16/52) = 3.076

The variance of X₂ is:

Var-X_{2} =3.076(1-(16/52))=2.13

The expect value of X is:

Xexp = MeanX₁ + MeanX₂ = 3.33 + 3.076 = 6.406

The variance of X is:

VarX = VarX₁ + VarX₂ = 2.775 + 2.13 = 4.905

The standard deviation is:

Xdevi = 4.905/2 = 2.45

b) The probability of drawing at least five six out of 20 rolls is equal to:

∑(1/6)ˣ(5/6)²⁰⁻ˣ = 0.231 with x = 5

The probability of at least 4 Jack, Queen, Kings or Aces is:

∑(16/52)ˣ(1-(16/52))¹⁰⁻ˣ = 0.37 with x = 4

The probability of given event is equal to:

P = 0.231 * 0.37 = 0.08547

5 0
3 years ago
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Vilka [71]
If you are looking for the value of N, multiply both sides by 4. The value of N is 4900.
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