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Zanzabum
3 years ago
8

Do the whole step then divide it by 2

Mathematics
1 answer:
alukav5142 [94]3 years ago
8 0

Answer:

That’s too tiny I cant read it

Step-by-step explanation:

You might be interested in
George Johnson recently inherited a large sum of money; he wants to use a portion of this money to set up a trust fund for his t
nikdorinn [45]

Answer:

a. B+S = 1

0.06B+0.1S \geq 0.075

B \geq 0.3

Objective function:

R=0.06B+0.1S

b) See Attached picture

30% in bonds and 70% in stocks

Step-by-step explanation:

a.

In order to solve the first part of the problem we need to take into account that the problem wants us to determine the percentage that should be allocated to each of the possible investment alternatives. In that case, the sum of the percentages must be equal to 1 (which means that we will have 100 of the trust fund)

so that gives us our first restriction for the problem.

B+S=1

Next, the problem tells us that the projected returns over the life of the investments are 6% for the bond fund and 10% for the stock fund. It also states that he wants to select a mix that will enable him to obtain a total return of at least 7.5%, so we can take this information and get the second restriction from it:

0.06B+0.1S \geq 0.075

Next, the problem tells us that whatever portion of the inheritance he finally decides to commit to the trust fund, he wants to invest at least 30% of that amount in the bond fund, so that's where the last restriction comes from:

B \geq 0.3

now, the idea is to optimize the investment, this is get the greatest amount of money out of the trust fund, so the objective function is:

R=0.06B+0.1S

which represents the return on the investment.

b)

For part b we can start by graphing each of the restrictions:

B+S = 1

This will be a single line, you can draw the line by setting B=0 first so you get:

0+S=1

S=1

So the first point to plot will be (0,1)

next, we can set s=0 to get:

B+0=1

B=1

so the second point to plot will be (1,0)

so you can plot the two points and connect them with a straight line. This is the green line on the uploaded graph.

Next we can graph the second restriction:

0.06B+0.1S \geq 0.075

we can use the same procedure we used for the previous graph, in this case the points would be:

(0 , 0.75) and (1.25, 0)

and again connect the two points with a straight line. Next we need to decide which region of the graph to shade for which we can pick two arbitrary points on each side of the line, for example we can pick:

(0,0) and (2,2) and see which one makes the inequality true:

for (0,0) we get:

0.06B+0.1S \geq 0.075

0.06(0)+0.1(0) \geq 0.075

0 \geq 0.075

Which is false, therefore we need to shade the other region of the graph:

for (2,2) we get:

0.06B+0.1S \geq 0.075

0.06(2)+0.1(2) \geq 0.075

0.32 \geq 0.075

Which is true, so we shade the region of the graph that contains that point. (see red graph)

now we graph the third restriction:

B \geq 0.3

In order to graph this third restriction we just need to draw a vertical line at B=0.3 and shade everything to the right of that line. (Blue graph)

Now, we can analyze the graph, in this case we need to locate the points where the green line crosses the red and the blue line which gives us the following coordinates:

(0.3, 0.7) and (0.625, 0.375)

these two points can be found by setting the first restriction equal to each of the other two restrictions if you are to do it algebraically. If you are using a graphing device, you can directly read them from the graphs.

So once we got those points, we can see which one gives us the greatest percentage of return.

let's test the first point (0.3, 0.7)

R=0.06B+0.1S

R=0.06(0.3)+0.1(0.7)

R=0.088

so this distribution gives us 8.8% in return, let's test the second point:

(0.625, 0.375)

R=0.06B+0.1S

R=0.06(0.625)+0.1(0.375)

R=0.075

so this distribution gives us 7.5% in return.

In this case the best distribution for us is 30% in bonds and 70% in the stock fund to get a return of 8.8%

6 0
3 years ago
y=-2x-7.A new path will be built perpendicular to this path. The paths will intersect at the point(-2,-3). Identify the equation
Over [174]

Answer:

y=1/2 x -2 is the perpendicular line equation

Step-by-step explanation:

y=1/2 x + b

solving for b:

-3=-1 +b

b==- 3+1 = -2

5 0
3 years ago
Note: Figure is not drawn to scale.
ycow [4]

Answer:130 I think I’m not real sure

Step-by-step explanation:

6 0
3 years ago
How many 5-digit numbers can be formed if each one uses all the digits 0,1,2,3,4
Anettt [7]

Answer:

{0, 1, 2, 3, 4} --> 96 5-digit numbers possible with this set.

Step-by-step explanation:

i dunno, i kinda just searched it up

link:   https://gmatclub.com/forum/how-many-five-digit-numbers-can-be-formed-using-digits-91597.html#:~:text=If%200%20is%20included%3A,numbers%20possible%20with%20this%20set.

5 0
3 years ago
Read 2 more answers
6. Find the HCF of : (a) 21xy³ and 24x²y² (b) 18ab and 36abc <br>(c) 4p³q²r , -12pr² , 16p²q²r²r²​
Simora [160]

Step-by-step explanation:

<h2><u>➤ </u><u>Solution :-</u></h2><h2>a)</h2>

Given monomials are 21 xy³ and 24x²y²

21 xy³ = 3×7×x×y×y×y

24x²y² = 3×8×x×x×y×y

HCF of 21xy³ and 24x²y²

=> 3×x×y×y

=> 3xy²

HCF of 21xy³ and 24x²y² = 3xy²

<h2>b)</h2>

Given monomials are 18 ab and 36abc

18 ab = 18×a×b

36abc = 2×18×a×b×c

HCF of 18 ab and 36abc

=> 18×a×b

=> 18ab

HCF of 18 ab and 36abc = 18ab

<h2>c)</h2>

Given monomials are 4p³q²r , -12pqr² and 16p²q²r²

4p³q²r = 4×p×p×p×q×q×r

-12pqr² = -3×4×p×q×r×r

16p²q²r² = 4×4×p×p×q×q×r×r

HCF of 4p³q²r , -12pqr² and 16p²q²r²

=> 4×p×q×r

=> 4pqr

HCF of 4p³q²r , -12pqr² and 16p²q²r² = 4pqr

<h2><u>Used Concept :-</u></h2>

→ The HCF of two or more numbers is the highest Common factor

→ The product of least common factors is the HCF of the numbers

3 0
3 years ago
Read 2 more answers
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