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leonid [27]
3 years ago
8

You watch a roulette wheel spin 270 consecutive times and the ball lands on a red slot each time. what is the probability that t

he ball will land on a red slot on the next spin
Mathematics
1 answer:
Rus_ich [418]3 years ago
6 0
<span>18/37 if you're in Europe, 9/19 if you're in America, assuming the wheel isn't rigged. If the roulette wheel is a fair wheel, the odds on any given spin of the wheel is unaffected by any previous spins of the wheel. So no matter how many times the wheel has consecutively come up red, the next spin can still come up red, black, or green based upon the number of each color is present on the wheel. The difference between the odds for Europe vs America has to do with a quirk about roulette. In Europe, the roulette wheel has 37 slots, 18 red, 18 black, and 1 green. In America, the roulette wheel has 38 slots, 18 red, 18 black, and 2 green. Although in this case, I'd be wary about assuming that the wheel isn't rigged. The odds of 270 consecutive red on a fair wheel is only 1 in 3.09663x10^84 in Europe, or 1 in 4.14949x10^87 in America.</span>
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In 2015 Michael purchased a stock for $45.80 a share. During the year he received $1.71 per share in cash dividends. At the end
timama [110]
Michael's initial investment is $45.80, the cost of the share. 
Michael Receives $1.71 in dividends.
He receives $47.50 for the stock when he sells it.
His profit on the sale of the stock is $47.50 - 45.80 = $1.70.
His total return on the stock is his total earnings, the dividends plus his profits on the sale of the stock, divided on what he paid initially, $45.80:
(1.71 + 1.70) ÷ 45.80 = .0744 = 7.45%
7.45% return on investment in less than a year, not bad!
Closest answer is 7.7%, not sure why it isn't exactly 7.45 or 7.5%. 

Answer is B) 7.7%
7 0
3 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
A three‐digit number satisfies the following conditions: The digits are consecutive whole numbers in increasing order; the sum o
IRINA_888 [86]
Answer: 123
They have to add up to 3 4 5 6 or 7 so it has to be that
4 0
3 years ago
If EF = 5w + 20, FG = 7w + 28, and EG = 72, find the value of w. Find EF and FG
IrinaK [193]

Answer:

 w = 2, EF = 30 , FG = 42

Explanation:

We have EF = 5w + 20  and FG = 7w + 28

 Since these points E, F and G are col-linear points we have.

    EG = EF + FG

  And given that EG = 72

So, EF+EG = 72

     5w + 20 + 7w + 28 = 72

     12w + 48 = 72

      12 w = 24

       w = 2

So EF = 5w + 20 = 5x2 + 20 = 30

     FG = 7w + 28 = 7x2 + 28 = 42

7 0
3 years ago
What’s the inequality of x-3&gt;8
sergiy2304 [10]

Answer:

x>11

Step-by-step explanation:

To simplify this inequality, we add 3 from both sides to get x-3+3>8+3. Since -3+3 cancels out to 0, we are left with x>8+3. 8+3=11 so x>11.

Hope this helps! If you need further explanation let me know :)

3 0
1 year ago
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