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alexandr402 [8]
3 years ago
13

How many timea does 2 go into 9

Mathematics
2 answers:
hram777 [196]3 years ago
7 0
2 goes into 9 4 times. 2+2=4+2=6+2=8. There are 4 twos, with 1 left over.

Hope this helps.
irina1246 [14]3 years ago
7 0
9/2
= 4 (r=1)

2 goes into 9 4 times (r=1)~
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( 1/2 )2 · ( 1/3 )2=?
Setler79 [48]

Answer:

2/3

Step-by-step explanation:

1/2 x 2/1 = 1/1

1/3 x 2/1= 2/3

2/3 x 1/1 = 2/3

6 0
3 years ago
Help me out. Mathmatics
Nina [5.8K]

Answer: A. 5.6267 X 10^8

Step-by-step explanation:

(5.62 X 10^8) + (6.7 X 10^5)= 562670000

Which has 8 numbers after 5

5.6267 X 10^8 has 8 as well just minus the zeroes

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Diona told me to get this app to solve my math problems,what is 10 + 10 Jean can't help because she's doing other stuff :,)​
elena55 [62]

Answer:

20

Step-by-step explanation:

10 + 10

= 20

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0 + 0 = 0

Then tens place.

1 + 1 = 2

So the number,

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5 0
3 years ago
5/6 divided by 1 and 1/2?
Tema [17]

Answer:

5/9

Step-by-step explanation:

(5/6)/1 1/2

5/9

Merry Christmas

6 0
3 years ago
A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. ​a) E
polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) \alpha =1-0.98=0.02

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq  p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and z_{\alpha/2} is the z-value that let a probability of \alpha/2 on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, \alpha by 0.02 and z_{\alpha/2} by 2.33

Where p' and \alpha are calculated as:

p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02

So, replacing the values we get:

0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq  p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence 1-\alpha is equal to 98%

It means the the level of significance \alpha is:

\alpha =1-0.98=0.02

4 0
3 years ago
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