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Ugo [173]
3 years ago
10

Ruth sees 11 flags in the park. Juno sees 4 more flags than Ruth. Sandra sees 9 more flags than Juno. How many flags does Sandra

see.
Mathematics
1 answer:
Irina-Kira [14]3 years ago
7 0
First you add 11+4 which equals 15 then you add 15+9 which equals 24. So Sandra sees 24 flags
You might be interested in
Devin is collecting signatures for a petition to open a new park in her town. She needs to collect at least 1,000 signatures bef
steposvetlana [31]

Answer:

The correct opion is;

7 ≤ p

Step-by-step explanation:

The number of signatures Devin needs to collect = 1,000 signatures

The numer of signatures Devin has already = 380 signatures

The number ofsignatures each petition page can hold = 80 signatures

Therefore;

The number of extra signatures required = 1,000 - 380 = 680 signatures

The number of petition pages required = 1,000 petitions /(80 signatures/page)   = 12.5 pages

The number of pages already filled = 380 petitions /(80 signatures/page) = 4.75 pages

The number of pages remaining, p = 12.5 - 4.75 = 7.75 pages

Therefore, 7 ≤ p.

8 0
3 years ago
Read 2 more answers
Can someone work out this problem for me because I do not get it and it is due tomorrow for homework? 83.971 + 10.9 PLSS HELPPPP
IrinaK [193]
If you are just adding those two decimals together, the answer would be 100.871.

83.971
+ 10.900 (make believe there are two zeros)
—————-
100.871
8 0
3 years ago
Read 2 more answers
Decimal 23.5 x 100 =
Alexeev081 [22]

Answer:

2350

Step-by-step explanation:

23.5 × 100 move the decimal point right by 2 because there's two 0

8 0
3 years ago
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Ava and Kelly ran a road race, starting from the same place at the same time. Ava ran at an average speed of 6 miles per hour. K
zalisa [80]
<h2>Hello!</h2>

The answer is:

It will took 0.375 hours for Ava and Kelly to be 3/4 miles apart.

<h2>Why?</h2>

To calculate how long after they start they will be 3/4 miles apart, we need to write two equations.

So, writing the equations, we have:

Calculations for Ava:

We have the following information,

v_{Ava}=6mph

Then, writing the equation,

x_{Ava}=x_{o}+v_{Ava}*t

x_{Ava}=x_{o}+v_{6mph}*t

Calculations for Kelly:

We have the following information,

v_{Kelly}=8mph

We need to calculate when Kelly will be 3/4 miles apart of Ava, so, it's position will be the Ava's position plus 3/4 miles.

Then, writing the equation,

x_{Ava}+0.75miles=x_{o}+v_{Kelly}*t

x_{Ava}+0.75miles=x_{o}+v_{8mph}*t

Now, substituting Ava's speed into the second equation, we have:

x_{o}+6mph*t+0.75miles=x_{o}+8mph*t

6mph*t+0.75miles=+8mph*t

8mph*t-6mph*t=0.75miles

2mph*t=0.75miles

t=\frac{0.75miles}{2mph}=0.375hours

Hence, we have that it will took 0.375 hours for Ava and Kelly to be 3/4 miles apart.

Have a nice day!

7 0
3 years ago
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Help plz!! i am stuck and confused plz help!!
fenix001 [56]
525 feet above the ground
7 0
3 years ago
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