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Hunter-Best [27]
3 years ago
15

24/48 as a whole number

Mathematics
1 answer:
Verdich [7]3 years ago
4 0
This isn’t possible. This can be a fraction, which is 1/2 in simplest terms. If you want to use a decimal, 0.5 is the answer.
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HELLO!!!!!!!!!!!????????????? ANYONE?!!!!!!!!!!!!!!!!!!!!!!!!!!! PLS??????????!!!!!!!!
bagirrra123 [75]

Answer:

i might be wrong but it thinks it's 6 to 3 or 6/3

Step-by-step explanation:

because of the 6 , 3 are rarely encountered so it would be 6/3

4 0
3 years ago
A jacket usually sells for $58.00. If the jacket is 40% off, and sales tax is 8%, what is the total price of the jacket, includi
natali 33 [55]

Answer:

ok buddy

Step-by-step explanation:

7 0
3 years ago
Is this equation have a solution or not<br> y = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D" id="TexFormula1" title=
Musya8 [376]

Answer:

No solution.

Step-by-step explanation:

y + 3x - 4y = 0 + 0.75x

- 3y + 3x = 0 + 0.75x

- 3y + 3x - 0.75x = 0 + 0.75x - 0.75x

- 3y + 2.25x = 0

7 0
3 years ago
todd curently has 5,000 what was the value of his money four years ago if hes earned 4% interest each year
coldgirl [10]
A(t)  = P (1+rt)

5000 = P ( 1 + 0.04 *4)

5000 = P (1.16)

P = 4310.34
6 0
4 years ago
Read 2 more answers
(08.01) Two lines, A and B, are represented by the following equations: Line A: 3x + 3y = 12 Line B: x + y = 4 Which statement i
UkoKoshka [18]

Answer: There are infinitely many solutions.

Step-by-step explanation:

Given, Two lines, A and B, are represented by the following equations:

Line A: 3x + 3y = 12

Line B: x + y = 4

By comparing to the equations a_1x+b_1x=c_1 and a_2x+b_2x=c_2 respectively , we have

a_1=3,\ b_1=3\ \ \&\ c_1=12\\\\a_2=1,\ b_2=1\ \ \&\ c_2=4

Now , \dfrac{a_1}{a_2}=\dfrac{3}{1},\ \dfrac{b_1}{b_2}=\dfrac{3}{1},\ \&\ \dfrac{c_1}{c_2}=\dfrac{12}{4}=\dfrac{3}{1}

i.e. \dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}

It implies the gives lines are co-incident (linearly dependent).

That means it has infinitely many solutions.

So, the correct answer is "There are infinitely many solutions.".

6 0
3 years ago
Read 2 more answers
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