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tangare [24]
3 years ago
15

Find the number, if the sum of 9 and a half a number equals 35. Which of the following translations is correct?

Mathematics
2 answers:
lianna [129]3 years ago
8 0
Let's translate “ the sum of 9 and a half a number equals 35 " into an equation which is:
9+1/2x=35
Or
9+x÷2=35
Solve:
9+1/2x=35
Subtract 9 to each side
9+1/2x-9=35-9
1/2x=26
Multiply 2 to each side
1/2x*2=26*2
x=52
It
9+x÷2=35
Subtract 9 to each side
9+x÷2-9=35-9
x÷2=26
Multiply 2 to each side
x÷2*2=26*2
x=52. As a result, the correct choices are 9+x÷2=35. Hope it help!
Alla [95]3 years ago
6 0
I think its the first choice
9+1/2x=35 is the original equation if you translate the words, but 9+x divided by 2=35 is equivalent
hope this helps!
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Answer:

8/15 left

Step-by-step explanation:

Given data

We want to perform subtraction operation on fractions

Total number of water= 5/6

we are told that 3/10 are for other runners

Hence the number of water left is

=5/6-3/10

=50-18/60

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Hence there are 8/15 left

8 0
3 years ago
Find the general solution of (x+3)y’=2y
gregori [183]

Answer:

y=C(x+3)^2

Step-by-step explanation:

We are given:

\displaystyle (x+3)y^\prime=2y

Separation of Variables:

\displaystyle \frac{1}{y}\frac{dy}{dx}=\frac{2}{x+3}

So:

\displaystyle \frac{dy}{y}=\frac{2}{x+3} \, dx

Integrate:

\displaystyle \int\frac{dy}{y}=\int\frac{2}{x+3}\, dx

Integrate:

\displaystyle \ln|y|=2\ln|x+3|+C

Raise both sides to e:

|y|=e^{2\ln|x+3|+C}

Simplify:

|y|=(e^{\ln|x+3|})^2\cdot e^C

So:

|y|=C|x+3|^2

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Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o
NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so \pi = 0.8.

(a) What is the probability she gets an A?

There are four problems, so n = 4

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find P(X \geq 3)

P(X \geq 3) = P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096

P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096

P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so n = 3

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find P(X \geq 2)

P(X \geq 3) = P(X = 2) + P(X = 3)

P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384

P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512

P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0
3 years ago
Find the distance between -6 - 8
Viefleur [7K]

Answer:

2

Number line.

We start at -6 or -8.

If we start from -6, we will be going __ spaces to the left until we get to -8.

Or start from -8 and go __ spaces to the right until you get to -6.

Then count the spaces.

You'll get 2.

4 0
3 years ago
Read 2 more answers
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