Step-by-step explanation:
Your problem → 5y+5/2 / 25y-20/40y^2-32y
5y+5/2÷25y-20/40y^2-32y
=5⋅y+5/2÷25×y-20/40×y^2-32×y
=5y+5/2÷25×y-20/40×y^2-32y
=5y+5/2×1/25×y-20/40×y^2-32y
=5y+y/10-20/40×y^2-32y
=5y+y/10-y^2/2-32y
=5y×10+y-y^2×5-32y×10 ÷ 10
=50y+y-5y2-320y ÷ 10
= -269y-5y^2 / 10
Answer:
Step-by-step explanation:
<u>Step 1: Pull a 7 from the top</u>
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<u>Step 2: Factor the bottom</u>
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<u>Step 3: Cancel the top (x+6) and the bottom (x+6)</u>
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Answer:
<h3>The value of A will be -3x^2 </h3>
By observing the table it can be concluded that the value of A must be equal to 3x × (-x)
So, the value will be -3x^2
Answer:5x times -7
Step-by-step explanation:
You ignore the brackets and move the 2x to the other side. Then move the 4 to the other side
