These are the events in the question above:
<span>D - has disease
</span>
<span>H - healthy (does not have disease)
</span>
<span>P - tests positive </span>
<span>It is the probability that a person has the disease AND tests positive divided by the probability that the person tests positive.
</span>
Sick, + [.04*.91] = .0364
<span>Sick, - [.04*.09] = .0036 </span>
Healthy, + [.96*.04] = 0.0384
<span>Healthy, - [.96*.96] = .9216
</span>
.0364 / (.0364 + .0.0384) = 0.487
The plane PRS passes through the points P, R and S. So it contains the line RS. Also the plane QRS passes through the points Q, R and S. So it contains the line RS as well. Since both the planes contain the line RS, the line RS must be the intersection of plane PRS and QRS
Answer:
Expression Derivatives
y = tan-1(x / a) dy/dx = a / (a2 + x2)
y = cot-1(x / a) dy/dx = - a / (a2 + x2)
y = sec-1(x / a) dy/dx = a / (x (x2 - a2)1/2)
y = cosec-1(x / a) dy/dx = - a / (x (x2 - a2)1/2)
Answer: D the difference of z and y must be 1/2x
Step-by-step explanation:
