Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Answer:
A
Step-by-step explanation:
omi god..... I used http://convert-to.com/202/speed-units.html and got
1.64 maybe if u try it would be different idk
<span>x=<span>−<span><span>2<span> and </span></span>y</span></span></span>=<span>−<span>2
</span></span>A.(−2, −2)