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Kaylis [27]
2 years ago
11

Baily has been measuring the growth of a flower. It has grown ¾ of an inch each week. It is now 3 inches tall. How many weeks ha

ve passed.?
Mathematics
2 answers:
Snezhnost [94]2 years ago
8 0
It has been 4 weeks.
finlep [7]2 years ago
6 0

Answer:

Step-by-step explanation:

Balls

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Ami and Bert are drawing plans for rectangular vegetable gardens. In Ami's plan, the garden is 16 feet by 13 feet. In Bert's pla
Nesterboy [21]

Answer:

A and B

16 times 13=208

18 times 18=324

Subtract those and you get 116

4 0
2 years ago
Read 2 more answers
I am having trouble with this problem. I need to find the lengths of this right triangle. How would you do this?
podryga [215]
You labeled the triangle wrong sides 'a' and 'b' are supposed to be the sides that make the right angle.  the other side is called the hypotenuse which is the longest side which you should have labeled 'c'

so Pythagorean theorem says
a^2+b^2=c^2
so
(2x+1)^2+(11x+5)^2=(12x+1)^2
distribute
(4x^2+4x+1)+(121x^2+110x+25)=(144x^2+24x+1)
add like terms
125x^2+114x+26=144x^2+24x+1
subtract 125x^2 from both sides
114x+26=19x^2+24x+1
subtract 114x from both sides
26=19x^2-90x+1
subtract 26 from both sides
0=19x^2-90-25
factor
(x-5)(19x+5)=0
therefor x-5=0 and/or 19x+5=0
so
x-5=0 add 5 to both sides
x=5
19x+5=0
subtract 5 from both sides
19x=-5
divide both sides by 19
x=-5/19
since side legnths can't be negative, we can cross this solution out

so x=5
subtitute
1+2x
1+2(5)
1+10=11
side a=11

11x+5
11(5)+5
55+5=60
side b=60

12x+1
12(5)+1
60+1=60
side c=61
add them all up
side a+b+c=11+60+61=132=total legnth
5 0
2 years ago
Find the dimensions of a rectangle whose width is 6 miles less than it’s length and whose are is 55 square miles.
SSSSS [86.1K]

area = width * length

or

A = W * L

55 = W * (W+6)

solve for width:

0 = W^2 + 6W - 55

this is a quadratic and has two solutions -11 and 5

a length can only be non-negative so discard -11.

width W = 5 miles

now the length is 5+6 = 11 miles


6 0
2 years ago
Read 2 more answers
A patient with high blood pressure who weighs 226 pounds is put on a diet to lose 26 pounds in 3 months. The patient loses 8 3 4
dimaraw [331]

Given :

A patient with high blood pressure who weighs 226 pounds is put on a diet to lose 26 pounds in 3 months. The patient loses 8 3/4 pounds the first month and 11 5/8 pounds the second month.

To Find :

How much weight must be lost the third month for the goal to be achieved.

Solution :

Let, weight lose in third month is x.

So, 8 3/4 + 11 5/8 + x = 26

\dfrac{32+3}{4}+\dfrac{88+5}{8}+x=26\\\\x = 26 - ( \dfrac{35}{4}+\dfrac{93}{8})\\\\x=5.625\ pounds

Therefore, weight lose in third month is 5.625 pounds.

Hence, this is the required solution.

3 0
2 years ago
Solution to y=6x^2+60x+20
dlinn [17]
The solution is on a graph with parallel lines
7 0
2 years ago
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