Add the 18, 16, and 8 together
Then subtract that number from 50.
18+16+8=42
50-42=8
So, 8 patrons don't like either.
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Answer:
- 2nd force: 99.91 lb
- resultant: 213.97 lb
Step-by-step explanation:
In the parallelogram shown, angle B is the supplement of angle DAB:
∠B = 180° -77°37' = 102°23'
Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.
Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.
BC/sin(A) = AB/sin(C)
AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb
AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb
Answer:
Step-by-step explanation:
hearing, taste, touch,
Hello!
To solve this we use the equation sin60 = (s/2) / (d/2)
s is a side of the triangle
d is the diameter
sin60 = s/d




put 6 in for s


d = 6.9
The answer is C) 6.9
Hope this helps!