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kogti [31]
3 years ago
15

What is the answer to the problem 229=133-y solve for y

Mathematics
1 answer:
marta [7]3 years ago
5 0
229-133 = -y
96/-1 = -y/-1
-96 = y
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C2 = 39<br><br> (c squared) <br><br> please help :(
iVinArrow [24]

<em>Answer:</em>

<em></em>\boxed{c = \sqrt{39} / c= - \sqrt{39} }<em></em>

<em>This " / " means or, btw!</em>

<em>Step-by-step explanation:</em>

<em></em>c^2 = 39<em></em>

<em>⇒Take square root.</em>

<em></em>c =<em> ± </em>\sqrt{39}<em></em>

<em></em>c = \sqrt{39}<em> or </em>c = -\sqrt{39}<em></em>

<em>Hope this helped you!</em>

7 0
3 years ago
PLZZ HELP! PLZ NO PLAGARISM!
arlik [135]

Answer: The area of Rhode Island is about 1,212 square miles

7 0
3 years ago
I Need The Answer Plz!!! Geometry Is Hard!!
prohojiy [21]

Answer:

12√5

Step-by-step explanation:

According to the attached sketch, there are 2 triangles which we need to focus on, triangle A (in yellow) and triangle B (In red).

If you look at triangle A, we notice that X is the hypotenuse of triangle A. This means that X must be the largest length in triangle A, hence we can say that x must be greater than 24 (or 24 < x)

Now look at triangle B, in this case, they hypotenuse is 30 and x is the length of one of the sides. This means that x must be shorter than the hypotenuse (i.e x < 30)

from the 2 paragraphs above, we can see now that we can assemble an inequality in x

24 < x < 30

If we look at the choices, we can immediately ignore 33 because x must be less than 30,

working out the choices, we find that the only choice which falls into the range 24<x<30 is the 2nd choice 12√5  (= 26.83)  (which is the answer)

The last 2 choices give values smaller than 24 and are hence cannot be the answer

8 0
3 years ago
Let X=[10 -3] and y=[-1 -5] then the distance between X and y is​
slavikrds [6]

Answer:

[11 2]

Step-by-step explanation:

10 to -1 is 11 and-3 to -5 is 2 therfore you have the distance of 11 and 2

3 0
3 years ago
Read 2 more answers
Simplify (Are all division)<br><br>2+4i<br>3i<br><br>3+2i<br>4+i<br><br>2i^11
Alla [95]

We\ know:\ i=\sqrt{-1}\to i^2=-1

\dfrac{2+4i}{3i}=\dfrac{2+4i}{3i}\cdot\dfrac{3i}{3i}=\dfrac{6i+12i^2}{9i^2}=\dfrac{6i+12(-1)}{9(-1)}\\\\=\dfrac{6i-12}{-9}=\dfrac{2i-4}{-3}=\dfrac{4}{3}-\dfrac{2}{3}i

\dfrac{3+2i}{4+i}=\dfrac{3+2i}{4+i}\cdot\dfrac{4-i}{4-i}=\dfrac{(3+2i)(4-i)}{4^2-i^2}\\\\=\dfrac{(3)(4)+(3)(-i)+(2i)(4)+(2i)(-i)}{16-(-1)}=\dfrac{12-3i+8i-2i^2}{16+1}\\\\=\dfrac{12+5i-2(-1)}{17}=\dfrac{12+5i+2}{17}=\dfrac{14+5i}{17}=\dfrac{14}{17}+\dfrac{5}{17}i

2i^{11}=2i^{10+1}=2i^{10}i^1=2i^{2\cdot5}i=2i(i^2)^5=2i(-1)^5=2i(-1)=-2i


Used:\ (a+b)(a-b)=a^2-b^2

6 0
3 years ago
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