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Verdich [7]
3 years ago
5

What is the solution to this equation?

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
8 0

Answer:

B. x= 5

Step-by-step explanation:

btw can i have brainliest please

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Write the equation of the line that passes through (-1,8) and is parallel to the graph of y = 4x - 2
NikAS [45]

Answer:

When a line is parallel to another line, they have the same slope. So far the equation would be, y=4x+b. To find the value of b, substitute the given point into the equation.

8=4(-1)+b

8=-4+b

b=12

So, the equation of the line is y=4x+12.

:)

8 0
2 years ago
how do you solve this problem what do you put on the empty boxes and graph please help me ASAP thanks in adavance
Alex17521 [72]
First column of (x) put {0,1,2,3,4} then substitute in the equation of y to get the y value for each x
then in each row you have (x,y) , so plot them on the graph and you will get a line
4 0
3 years ago
Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha
const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

P(1.83\leq X\leq  a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06

Thus, the value of <em>a</em> is 12.06.

7 0
3 years ago
What is the solution to the equation 6x+2=9x-1?<br> 0 0 0 0<br> X= 1
Stells [14]

Answer:

Step-by-step explanation:

6x+2=9x-1      x=1

6(1)+2=9(1)-1

6+2=9-1

8=8

Hope this helps :)

8 0
3 years ago
Read 2 more answers
SHOW YOUR WORK! ??????????
Verizon [17]

Answer:

<h3>m = - 4</h3>

<h2>Solved in the attachment!! </h2>

Step-by-step explanation:

<h2>HOPE IT HELPS YOU!!</h2>

7 0
2 years ago
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