Solve for a using the equation. Hope that helps!
She will need a one to one ratio so to get to your ratio you need to take your 3 to 1 ratio and divide it by the 1 on 1 ratio
F(x) = -3(x + 2)(x - 5)^3 > 0
(x + 2)(x - 5) > 0
x + 2 > 0 or x - 5 < 0
x > -2 or x < 5
-2 < x < 5
Therefore, the stated interval is false.