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3 years ago

A cyclist does work at the rate of 500 w while riding. how much force does her foot push with when she is traveling at 8.0 m/s?

Physics

2 answers:

NikAS [45]3 years ago

7 0

P=F*V
F=P/V
F=500W/8=62.5N

yanalaym [24]3 years ago

4 0

Answer:

The foot push of the cyclist exerted a force of 63 Newton.

Explanation:

Given data

Power (P): 500 Watt

Velocity (v): 8.0 m/s

Force (F): ?

We can find the force exerted by the foot push of the cyclist using the following expression.

P = F × v

v = P/F = 500 W/ (8.0 m/s) = 63 N

The foot push of the cyclist exerted a force of 63 Newton.

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If the pipe of the previous exercise is connected to a hose and the speed there is 3.8 m/s, what is the diameter of the hose?

Amiraneli [1.4K]

The diameter of the hose is 6.34 cm.

"Your question is not complete, it seems to be missing the following information";

the flow rate of water in the pipe is 0.012 m³/s

The given parameters;

velocity of water in the hose, v = 3.8 m/s

flow rate of water in the hose, Q = 0.012 m³/s

Volumetric flow rate is directly proportional to the product of the area of the hose through which the water flows and the velocity of the water flowing through the hose.

Q = Av

where;

Q is the volumetric flow rate

A is the area of the hose

v is the velocity of flow

The area of the hose is calculated as follow;

$A = \frac{Q}{v} \\\\A = \frac{0.012}{3.8} \\\\A = 0.00316 \ m^2$

The diameter of the hose is calculated as follows;

$A = \frac{\pi D^2}{4} \\\\\pi D^2 = 4A\\\\D^2 = \frac{4 \times A}{\pi} \\\\D = \sqrt{\frac{4 \times A}{\pi} } \\\\D = \sqrt{\frac{4 \times 0.00316}{\pi} } \\\\D = 0.0634 \ m\\\\D = 6.34 \ cm$

Thus, the diameter of the hose is 6.34 cm.

Learn more here: brainly.com/question/15061170

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