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3 years ago

What is the speed of a bobsled whose distance-time graph indicates that it traveled 119m in 29s?

Physics

2 answers:

Assoli18 [71]3 years ago

7 0

Do 112m /29s which it will be 3.862 which if you round it, it will be 3.86 m/s

solmaris [256]3 years ago

5 0

So, for every 1 second, how many meters did the bobsled travel? Do this by dividing 119 by 29. This answer will be meters per second. If you need meters per minute, simply multiply by 60.

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In designing circular rides for amusement parks, mechanical engineers must consider how small variations in certain parameters c

Bess [88]

Answer:

Part a)

$dF = -\frac{mv^2}{r^2} dr$

Part b)

$dF = \frac{2mvdv}{r}$

Part c)

$dT = - \frac{2\pi r}{v^2} dv$

Explanation:

Part a)

As we know that force on the passenger while moving in circle is given as

$F = \frac{mv^2}{r}$

now variation in force is given as

$dF = -\frac{mv^2}{r^2} dr$

here speed is constant

Part b)

Now if the variation in force is required such that r is constant then we will have

$F = \frac{mv^2}{r}$

so we have

$dF = \frac{2mvdv}{r}$

Part c)

As we know that time period of the circular motion is given as

$T = \frac{2\pi r}{v}$

so here if radius is constant then variation in time period is given as

$dT = - \frac{2\pi r}{v^2} dv$

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3 years ago

A standing wave is created on a string of length 1.2 m. If the speed of the wave on the string is 60.0 m/s, what is the fundamen

coldgirl [10]

Answer:

Fundamental frequency in the string will be 25 Hz

Explanation:

We have given length of the string L = 1.2 m

Speed of the wave on the string v = 60 m/sec

We have to find the fundamental frequency

Fundamental frequency in the string is equal to $f=\frac{v}{2L}$ , here v is velocity on the string and L is the length of the string

So frequency will be equal to $f=\frac{v}{2L}=\frac{60}{2\times 1.2}=25Hz$

So fundamental frequency will be 25 Hz

6 0

3 years ago

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Answer:

The component form will be;

In the x-axis = 121.73 due west

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Explanation:

An image of the calculation has been attached

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2 years ago

A jet begins a flight along a path due north at 300 miles per hour. A wind is blowing due west at 30 miles per hour. Find the re

schepotkina [342]

Answer:

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Explanation:

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2 years ago

Martije has made a slight error in naming a compound monocarbon tetrabromide. What compound is she most likely naming, and what

Alik [6]

Answer: $CBr_4$ : carbon tetrabromide

Explanation:

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The naming of covalent compound is given by:

1. The less electronegative element is written first.

2. The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.

3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.

Hence, the correct name for $CBr_4$ is carbon tetrabromide.

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3 years ago

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