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quester [9]
3 years ago
8

What is the speed of a bobsled whose distance-time graph indicates that it traveled 119m in 29s?

Physics
2 answers:
Assoli18 [71]3 years ago
7 0
Do 112m /29s which it will be 3.862 which if you round it, it will be 3.86 m/s
solmaris [256]3 years ago
5 0
So, for every 1 second, how many meters did the bobsled travel? Do this by dividing 119 by 29. This answer will be meters per second. If you need meters per minute, simply multiply by 60.
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Water vapor enters a turbine operating at steady state at 500°C, 40 bar, with a velocity of 200 m/s, and expands adiabatically t
faltersainse [42]

Answer:

W = 5701 KW

Explanation:

From the question let inlet be labelled as point 1 and exit as point 2, for the fluid steam, we can get the following;

Inlet (1): P1 = 40 bar ; T1 = 500°C and V1 = 200 m/s

Exit(2) : At saturated vapour; P2 = 0.8 bar and V2 = 150 m/s

Volumetric flow rate = 15 m^(3)/s

Now, to solve this question, we assume constant average values, steeady flow and adiabatic flow.

Specific volume for steam at P2 = 0.8 bar in the saturated vapour state can be gotten from saturated steam tables(find a sample of the table attached to this answer).

So from the table,

v2 = 2.087 m^(3)/kg

Now, mass flow rate (m) = (AV) /v

Where AV is the volumetric flow rate.

Thus, the mass flow rate at exit could be calculated as;

m = 15/(2.087) = 7.17 kg/s

We also know energy equation could be defined as;

Q-W = m[(h1 - h2) + {(V2(^2) - (V1(^2)} /2)} + g(Z2 - Z1)]

Since the flow is adiabatic, potential energy can be taken to be zero. Therefore, we get;

-W = m[(h2 - h1) + {(V2(^2) - (V1(^2)} /2)}

From, table 2, i attached , at P1 = 40 bar and T1 = 500°C; specific enthalpy was calculated to be h1 = 3445.3 KJ/Kg

Likewise, at P2 = 0.8 bar; from the table, we get specific enthalpy as;

h2 = 2665.8 KJ/Kg

So we now calculate power developed;

W = - 7.17 [(2665.8 - 3445.3) + {(150^(2) - 200^(2))/2000 = 5701KW

Since the sign is not negative but positive, it means that the power is developed from the system.

4 0
2 years ago
1 point
Sav [38]

Answer:

388.5J

Explanation:

Given parameters:

Weight  = 70N

Height  = 5.55m

Unknown:

Gravitational potential energy at the top of the ladder  = ?

Solution:

The gravitational potential energy is the energy due to the position of the body.

  Gravitational potential energy  = Weight x height

So;

 Gravitational potential energy  = 70 x 5.55 = 388.5J

8 0
2 years ago
A car accelerates from 4 meters/second to 16 meters/second in 4 seconds. The car’s acceleration is __meters/second2.
Mariana [72]
3 meters/second2
a=v-u/t
3 0
3 years ago
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Which of the following is an exercise myth?
Margaret [11]
The answere is No pain, no gain
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3 years ago
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A particle moves at a constant speed of 34 m/s in a circular path of radius 6.3 m. From this information, what can be calculated
Yakvenalex [24]

Answer:

Centripetal acceleration

Explanation:

  • The centripetal acceleration is the motion inwards towards the center of a circular path.
  • <em><u>Centripetal acceleration is given by; the square of the velocity, divided by the radius of the circular path. </u></em>
  • That is;

         ac = v²/r

         Where; ac = acceleration, centripetal, m/s², v is the velocity, m/s and r is the  radius, m

3 0
3 years ago
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