Question

What are the values of a, b, and c in the quadratic equation 0 = x2 – 3x – 2?

Answer 1

For this case we have that by definition, a quadratic equation is of the form:

$ax ^ 2 + bx + c = 0$

Where the roots are given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

We have the following equation:

$x ^ 2-3x-2 = 0$

Then, according to the definition, the values are:

$a = 1\\b = -3\\c = -2$

Answer:

$a = 1\\b = -3\\c = -2$

Answer 2

Answer:

The values of a, b, and c in the quadratic equation are:

$a=1\\b=-3\\c=-2$

Step-by-step explanation:

The general form of a quadratic equation is as follows

$ax^2 + bx +c$

Where a, b and c are real numbers that represent the coefficients of the quadratic equation and $a \neq 0$

In this case we have the following quadratic equation

$x^2 - 3x - 2$

Therefore, notice that:

$a=1\\b=-3\\c=-2$