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2 years ago

Write (1/6) to the 3rd power as a product of the same factor.then find the value

Mathematics

1 answer:

andreyandreev [35.5K]2 years ago

3 0

1/216 don’t forget to simplify

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use digits to write a number for the following. : seven tenths . three hundreths, and eight thousandths and then (. )

kondor19780726 [428]

Answer:

0.0378

Step-by-step explanation:

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2 years ago

I NEED HELP cube with 7cm3 sides and the mass is 210g

prisoha [69]

Answer:

300

Step-by-step explanation:

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3 years ago

Dr. Burger rides his bike to work in the mornings. Usually, he leaves his house at 8:20 and gets to the office at 9:00 riding at

Vika [28.1K]

Answer:

40 mph

Step-by-step explanation:

40 mins to bike usually, which means he bikes 10 miles. He needs to bike at a minimum of 10 miles in 15 mins, which translates to 40 miles in an hour.

P.S. He is going to surely be late.

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2 years ago

Let pn, n = 0,1,2,..., be the probability that an automobile policyholder will file for n claims in a five-year period. the actu

lara31 [8.8K]

P(1 claim) = p/4
P(2 claims) = (p/4)/4 = p/16

You should see that the distribution follows a geometric series with common ratio 1/4.
Sum geometric = (first term) / (1 - common ratio) = p/(1 - 1/4) = 4p/3

But the sum of all the probabilites must equal 1 ----> 4p/3 = 1 ----> p = 3/4

P(2 or more claims) = 1 - P(0 claims) - P(1 claim) = 1 - 3/4 - 3/16 = 1/16

3 0

3 years ago

The manufacturer of the ColorSmart-5000 television set claims 95 percent of its sets last at least five years without needing a

patriot [66]

Answer:

Step-by-step explanation:

Hello!

Your study variable is X: "number of ColorSmart-5000 that didn't need repairs after 5 years of use, in a sample of 390"

X~Bi (n;ρ)

ρ: population proportion of ColorSmart-5000 that didn't need repairs after 5 years of use. ρ = 0.95

n= 390

x= 303

sample proportion ^ρ: x/n = 303/390 = 0.776 ≅ 0.78

Applying the Central Limit Theorem you approximate the distribution of the sample proportion to normal to obtain the statistic to use.

You are asked to estimate the population proportion of televisions that didn't require repairs with a confidence interval, the formula is:

^ρ± $Z_{1-\alpha /2}$ * √[(^ρ(1-^ρ))/n]

$Z_{1-\alpha /2}$ = $Z_{0.995}$ = 2.58

0.78±2.58* √[(0.78(1-0.78))/390]

0.0541

[0.726;0.834]

With a confidence level of 99% you'd expect that the interval [0.726;0.834] contains the true value of the proportion of ColorSmart-5000 that didn't need repairs after 5 years of use.

I hope it helps!

7 0

3 years ago