i think y= b^x because it is only the odd one from the group
Answer:
Ordered pair, (1, 5/2) does not satisfy the given equation 3x-3y=-3
Step-by-step explanation:
![3x-3y=-3](https://tex.z-dn.net/?f=3x-3y%3D-3)
Here ![(x, y) = (1, \frac{5}{2} )](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%3D%20%281%2C%20%5Cfrac%7B5%7D%7B2%7D%20%29)
![3(1)-3(\frac{5}{2} )=-3](https://tex.z-dn.net/?f=3%281%29-3%28%5Cfrac%7B5%7D%7B2%7D%20%29%3D-3)
![3- (\frac{15}{2} )=-3\\6-15=-6\\-9\neq -6](https://tex.z-dn.net/?f=3-%20%28%5Cfrac%7B15%7D%7B2%7D%20%29%3D-3%5C%5C6-15%3D-6%5C%5C-9%5Cneq%20-6)
(x + 1)·(x + 1 + 11) = (x + 4)·(x + 4 + 1) --> x = 2
Tools like "photomath" are able to help you solving such equations.
Answer:
y = -5x - 17
Step-by-step explanation:
Linear equations, or lines, that are perpendicular to each other have opposite reciprocals for the value of slope. For the given line, y = 1/5x - 2, the slope is 1/5 and the opposite reciprocal is -5.
Given the value of the slope and a given point on the second line, you can solve for 'b':
y = mx + b
8 = (-5)(-5) + b
8 = 25 + b
-17 = b
y = -5x - 17