We have to solve x in terms of a, b and c:
a x - 3 b = c
a x - 3 b + 3 b = c + 3 b
a x = c + 3 b
x = ( c + 3 b ) : a
Answer:
4 ) ( c + 3 b ) / a
(4/2)^2*3.4*4
2^2*3.4*4
4*3.4*4
13.6*4
54.4
(4/2)^2*3.4*4
2^2*3.4*4
4*1.7*4
6.8*4
27.2
the answer is 54.4 or the answer is 27.2, i can't quite figure it out but those are my best guesses
4%• x =56
x=56•100/4
x=5600/4
x=1400
Answer:
45
Step-by-step explanation:
Simply start by listing out the numbers from smallest to largest.
We start out with the smallest number following this information being the number 10. The next are 21 and 20. The next are 32, 31, and 30. We can start to see a pattern. If the ten's digit is n, then there are n numbers within that ten-group that have a greater 10's digit than unit's digit. The largest ten-group (90 to 98) has 9 integers following the rules established. Thus, the number of 2-digit integers that have ten's digits greater than units digit is 1+2+3+...+9=45
IAnswer:
One possible solution is 450 and there are many more
Step-by-step explanation:
100,200,300
