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2 years ago

Which of these is also (always) a rhombus? (Select all that apply.)

Mathematics

2 answers:

Snezhnost [94]2 years ago

3 0

Answer:

A square and maybe a kite.

Step-by-step explanation:

Assoli18 [71]2 years ago

3 0

Answer:

D. Square

Step-by-step explanation:

Here is a good images that explains what is what:

Read it from bottom to top. It cannot be reversed.

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11) Write the explicit formula

Illusion [34]

Answer:

365

Step-by-step explanation:

tn = t1 + (n - 1)(d)

t(47) = -3 + (47 - 1)(8)

t(47) = -3 + (46)(8)

t(47) = -3 + 368

t(47) = 365

6 0

2 years ago

9. If 15 men working 10 days earn $500. How much will 12 men earn working 14,

Leno4ka [110]

Answer:

Firstly need to understand the questions.

If 15 men working 10 days, They earn 500.

If 12 men working 14 days, how much they will earn?

Step-by-step explanation:

560

Solution:

15 men working for 10 days =500

1 man working for 1 day = 500/(10*15) =10/3

Now 12 men working for 14 days = 12*14*10/3 =560.

I am pretty sure that answer is right.

Thank you :)

6 0

2 years ago

What is -2(4n - 1) +15<br> I think that it is -8n - 13 but i am not sure plz help

ANEK [815]

Answer: Your right!

-8n-13

Step-by-step explanation:

-2(4n-1)+15=

-8n+2-15

Combine like terms- 2-5= -13

so -8n-13

8 0

3 years ago

Matthew is using a microscope in science class. The microscope magnified the specimen 4x10^2 . If the specimen is 3cm long how l

choli [55]

Answer:

12 meters

Step-by-step explanation:

The apparent size is ...

(4·10^2)·(3 cm) = 12·10^2 cm = 12 m

___

1 m = 10^2 cm

5 0

2 years ago

A village fete has a children’s running race each year, run in heats of up to ten children. For each heat the first three contes

bekas [8.4K]

Answer: 1) 1/3,654 2) 3/406 3) 72,684,900,288,000 4) 120

<u>Step-by-step explanation:</u>

1) First and Second and Third

$\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}\times \dfrac{1\ remaining\ prize}{27\ remaining\ people}=\dfrac{6}{21,924}\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad =\large\boxed{\dfrac{1}{3,654}}$

2) First and Second

$\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}=\dfrac{6}{812}=\large\boxed{\dfrac{13}{406}}$

$3)\quad \dfrac{29!}{(29-10)!}=\large\boxed{72,684,900,288,000}$

$4)\quad _{10}C_3=\dfrac{10!}{3!(10-3)!}=\large\boxed{120}$

8 0

3 years ago