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3 years ago

Again, will give a brainlest answer!

Mathematics

2 answers:

max2010maxim [7]3 years ago

3 0

I think what is already filled in is correct

n200080 [17]3 years ago

3 0

I think the same i think the answer that is filled in is correct

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A coin was flipped 150 times. The results of the experiment are shown in the following table:

Wewaii [24]

<span>It is 10% higher than the theoretical probability.</span>

4 0

3 years ago

Which value or values would make this equation true? [?]=9

AlexFokin [52]

A. 9 only bc only 9 can be equal to 9 if it was absolutely value then the answer would be 9 and -9

6 0

2 years ago

Which equation has a graph that goes through the points (4, -6) and (0, 6)?

Ugo [173]

Answer:

$y = -3x + 6\\$

Step-by-step explanation:

Find the gradient of the equation

$\frac{Difference in y}{Difference in x} \\\\\frac{6 - - 6}{0 - 4} = \frac{12}{-4} = -3$

The equation will have the gradient -3x

Use the general equation of a line, and substitute the coordinates in to find the y-intercept.

$y = x + c\\ y = -3x + c\\$

(4, -6)

$-6 = -3(4) + c\\ -6 = -12 + c\\ -6 + 12 = c\\ c = 6$ $6 = -3(0) + c\\ 6 = 0 + c\\ c = 6$

(0, 6)

$6 = -3(0) + c\\ 6 = -0 + c\\ c = 6$

The equation of the line is

$y = -3x + 6\\$

4 0

3 years ago

Describe how the graph of y=log (10 000x) is related to the graph of y=log x

Nana76 [90]

Background: log (a . b) = log a + log b
hence log(10000x) = log 10000 + log x but we know that log 10000 = 4
= 4 + log x
therefore the graph of log(10000x) is just the graph of log x transposed by 4

5 0

3 years ago

Suppose that there are five young women and six young men on an island. Each woman is willing to marry some of the men on the is

pochemuha

Answer:

Based on the current information, the last man remaining unmarried will be a choice between two

Jason marries Anna

Matt marries Elizabeth

Kevin marries Barbara

Larry marries Diane

Carol can marry either Nick or Oscar

Step-by-step explanation:

The basic method to sort which woman will be marrying which man is simple.

We have to extract the choice by comparing choices of each woman side by side and then selecting the least common one and hence sorting one by one.

First, let's name all the women and men

1. Anna

2. Barbara

3. Carol

4. Diane

5. Elizabeth

We will refer to them with the initial letter of their name . A for Anna, B for Barbara, C for Carol, D for Diane, E for Elizabeth.

The men :

1. Jason

2. Larry

3. Matt

4. Kevin

5. Oscar

6. Nick

And they will be referred as J for Jason, L for Larry, M for Matt, K for Kevin, O for Oscar and N for Nick.

Options for A : J , L ,M

Options for B : K, L

Options for C : J, N , O

Options for D : J, L , N , O

Options for E : J, M

As we can see , no one else wants Kevin other than Barbara so :

Kevin marries Barbara

Moving onwards:

Elizabeth can marry either Jason or Matt,

Meanwhile Anna can marry either Jason , Larry or Matt

Hence,

Matt marries Eilzabeth

as Anna has two more choices still which are Jason and Larry.

Further, seeing the options for Carol and Diane

Carol can marry either Jason, Nick or Oscar while Diane can marry Larry as well as Jason , Nick and Oscar

We can select Jason as the match for Anna as Larry is also a choice for Diane.

Hence, Jason marries Anna

Now we are left with Larry , Nick and Oscar.

Since Carol can only decide from Nick and Oscar but Diane can decide from Larry, Nick and Oscar. Larry is the ideal option for Diane

so, Larry marries Diane

Now in the end, Carol can either choose between Nick or Oscar.

If she chooses Nick to marry, Oscar is left single

If she chooses Oscar to marry, Nick is left single.

7 0

2 years ago