Answer:
C. 8 units right and 5 units down
Step-by-step explanation:
since it's only a translation, take one point as an example. lets say the bottom right point on trapezoid P is point A, and the translated point on P' is A'. the coordinates of A are (-3,2) while the coordinates of A' are (5,-3). (-3+x,2+y)=(5,-3). -3+x=5, x=8; 2+y=-3, y=-5
Answer:
(a) f'(1)=-4
(b) y+4x-4=0
Step-by-step explanation:
<u>Tangent Line of a Function</u>
Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.
We are given

The derivative is

(a) The slope of the tangent line at (1,0) is


(b) The equation of the tangent line can be found with the general formula of the line:

Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus

Or, equivalently

Right answer is C
We can solve it with the formula
y=mx+b
b is the point where graphic starts
Table C shows us 0 by x, and -4 by y
So the graph starts at (0, -4 )
Answer:
-2
Step-by-step explanation:
Gradient/slope =