Given:
The power generated by an electrical circuit (in watts) as a function of its current x (in amperes) is modeled by
To find:
The current which will produce the maximum power.
Solution:
We have,
Differentiate with respect to x.
...(i)
To find the extreme point equate P'(x)=0.
Divide both sides by -30.
Differentiate (i) with respect to x.
(Maximum)
It means, the given function is maximum at x=4.
Therefore, the current of 4 amperes will produce the maximum power.
The greatest whole number that rounds to 2,500 is 2,549. The least whole number that rounds to 2,500 is 2,450.
Answer:r=3q+2/3
Step-by-step explanation:
Step 1: Flip the equation.
3r-6=9q-4
Step 2: Add 6 to both sides.
3r-6+6=9q-4+6
3r=9q+2
Step 3: Divide both sides by 3.
3r/3=9q+2/3
r=3q+2/3
Hopefully it’s right
Answer:
y = m x + b equation of a straight line
m m' = -1 condition for perpendicular lines
If y = 4 x - 7 then m = 4 so m' = -.25
Y = -.25 X + A we need to find A
A = Y + .25 * 8 = 2 + 2 = 4
Y = -.25 X + 4
Check:
2 = -.25 * 8 + 4 = -2 + 4 = 2
For the equation,
y = 1/2(x+3)^2 -5
The vertice is (-3,-5). Therefore the axis of symmetry is X = -3.
