Answer:
3200
Step-by-step explanation:
Based on your question that ask where each situation and the sampling frame doesn't match the population, resulting in under coverage. The possible answer to your question is , under coverage in a random sampling where the result that you get is still just a partial of the whole but it could be done in anytime as long as the number of people are still there. It means that the sampling result do not just base in one session of sampling.
Answer:

Step-by-step explanation:
<u><em>The correct question is</em></u>
Devon needs a wood board with an area of 5/16 square yard to complete a project. If the wood board is 1/3 yard wide, how long must the board be?
we know that
The area of a rectangle is equal to

where
L is the length
W is the width
we have

substitute

solve for L


Answer:
40
Step-by-step explanation:
5(8)
We know that
<span>Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another.
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.
</span>we have that
<span>Circle 1 is centered at (4,3) and has a radius of 5 centimeters
</span><span> Circle 2 is centered at (6,-2) and has a radius of 15 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the center of the circle 2
</span>the transformation has the following rule
(x,y)--------> (x+2,y-5)
so
(4,3)------> (4+2,3-5)-----> (6,-2)
so
center circle 1 is now equal to center circle 2
<span>The circles are now concentric (they have the same center)
</span>
step 2
A dilation is needed to increase the size of circle 1<span> to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle 1-----> 15/5----> 3
radius circle 1 will be=5*scale factor-----> 5*3-----> 15 cm
radius circle 1 is now equal to radius circle 2
A translation, followed by a dilation<span> will map one circle onto the other, thus proving that the circles are similar</span>