Answer:
The approximate solution to the system is 
.
Step-by-step explanation:
To solve the system of equations 
you must:
The approximate solutions to the system of equations are:
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
here's the right answer!
A) 76 + 80 + 78 + x = 82 times 4
234 + x = 328
x = 94
B) Mei needs a score of at least 94 on the next exam.
hope you have a good day
Answer: £54.60
Step-by-step explanation:
7.80 x 7 = £54.60
***If you found my answer helpful, please give me the brainliest. :) ***
