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ipn [44]
3 years ago
13

Which shape can have only one symmetry line?

Mathematics
2 answers:
Goshia [24]3 years ago
5 0
Isosceles Triangle(two sides equal, two angles equal)1 Line of Symmetry.

zvonat [6]3 years ago
3 0
An isosceles triangle
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Please help!! will give brainliest!
raketka [301]

Answer:

Angle EDC = Angle ADC

(Reflexive property)

ABD ~ ECD because all angles are congruent

If two are congruent, third one has to be as well since total angle is 180 each

3 0
3 years ago
GEOMETRY HELP PLEASE!
Mariana [72]

Answer:

(1, 2 )

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y ), thus

C(1, - 2 )  → C'(1, 2 )

5 0
3 years ago
7(3b-1)=2b-26 please help and give me step by step ☺️​
Colt1911 [192]

Answer:

b = -1

Step-by-step explanation:

7(3b-1): 7 goes into the numbers by multiplying. This will give you 21b-7.

So now the equation should be like 21b-7=2b-26.

-7 and 2b swap places, making 21b-2b=7-26. It will give you 19b= -19.

Finally divide the two numbers (-19 / 19) and the solution will be b= -1.

If I didn't make a clear answer or a good explanation, please comment. I sometimes mess up my steps, and this is my first time using this.

5 0
3 years ago
Read 2 more answers
Help me out, thank you.
AveGali [126]

Answer: 38

Step-by-step explanation:

7 0
3 years ago
In a statistics class there are 18 juniors and 10 seniors; 6 of the seniors are females and 12 of the juniors are males. If a st
White raven [17]

Answer:

a) 0.857

b) 0.571

c) 1

Step-by-step explanation:

Based on the data given, we have

  • 18 juniors
  • 10 seniors
  • 6 female seniors
  • 10-6 = 4 male seniors
  • 12 junior males
  • 18-12 = 6 junior female
  • 6+6 = 12 female
  • 4+12 = 16 male
  • A total of 28 students

The probability of each union of events is obtained by summing the probabilities of the separated events and substracting the intersection. I will abbreviate female by F, junior by J, male by M, senior by S. We have

  • P(J U F) = P(J) + P(F) - P(JF) = 18/28+12/28-6/28 = 24/28 = 0.857
  • P(S U F) = P(S) + P(F) - P(SF) = 10/28 + 12/28 - 6/28 = 16/28 = 0.571
  • P(J U S) = P(J) + P(S) - P(JS) = 18/28 + 10/28 - 0 = 1

Note that a student cant be Junior and Senior at the same time, so the probability of the combined event is 0. The probability of the union is 1 because every student is either Junior or Senior.

3 0
3 years ago
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