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3 years ago

Find the value of x and y

Mathematics

1 answer:

algol133 years ago

8 0

What do we know about these angles? Immediately, you might notice that (4y-8)° and (16x-4)° share a line. The same is true of (16x-4)° and (14x+4)°. Any straight line forms what's called a straight angle, which measures 180°, so we know that, since they add up to form a straight angle, (14x+4)° and (16x-4)° must add up to 180°. We can use that fact to set up an equation to solve for x:

(14x+4)+(16x-4)=180

After you solve for x, you should look to solve for y. How can we figure out what y is? If you're familiar with the vertical angle theorem, you'll know that all vertical angles (angles that are directly across from each other diagonally) are equal. So we know that 14x+4=4y-8. You can use the value of x you solved for before to solve this one fairly easily, and then you'll have both values.

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Agree & disagree statements: CIrcles

likoan [24]

Answer:

1. False

2. True

3. true

Step-by-step explanation:

The first answer is false, the second one is true and the third is true

6 0

2 years ago

Mold grows on bread and every day it doubles by the eighth day the entire bread is covered with mold when was half the bread cov

Brut [27]

Answer:

The mold will cover half the area as much are one day before it.

Step-by-step explanation:

Given:

Every day the mold on bread grows doubles

And by 8th day entire bread covered with it.

To Find:

When was half the bread covered by mold.

Solution:

It is said that area covered by mold doubles on each day

Total days taken to cover entire bread are 8

Let Area of bread be A

So Area covered (A) corresponds to 8 days with doubling.

So on previous day it should What ever area on 8th day/2

i.e A(8)/2

Similar on 6th day A(7)/2

So on 5ht day =A(6)/2 ,4th= A(5)/2, on 3rd= A(4)/2, on 2nd=A(3)/2

On 1st =A(2)/2

So we required Area= half of total.

One day before the 8th day will be 7th day

on that day it will cover half are so that on next day will cover the double of the previous area consumed.

4 0

3 years ago

Two semicircles are attached to the sides of a rectangle as shown.

melomori [17]

Answer:

$157\ in^{2}$

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle plus the area of two semicircles

The area of rectangle is equal to

$A=14*5=70\ in^{2}$

The area of the small semicircle is equal to

$A=\pi r^{2} /2$

$r=5/2=2.5\ in$ -----> radius is half the diameter

substitute

$A=(3.14)(2.5^{2})/2=9.8125 in^{2}$

The area of the larger semicircle is equal to

$A=\pi r^{2} /2$

$r=14/2=7\ in$ -----> radius is half the diameter

substitute

$A=(3.14)(7^{2})/2=76.93\ in^{2}$

The area of the figure is equal to

$70+9.8125+76.93=156.7425=157\ in^{2}$

8 0

3 years ago

Read 2 more answers

Emi made a 90 on her math test. There was 60 problems on her test. How many did she miss?

viva [34]

If she made a 90 that means 90 percent aka .90 so multiply that by 60 to get 54 right aka 6 wrong which you could find either by subtracting 54 from 60 or solving for 10 percent bc she got that much wrong and multiply .10x60=6 wrong

3 0

3 years ago

Robert borrowed $750 from his parents. He promised to repay the loan by giving his parents at least $67 from his paycheck each w

Luda [366]

To answer this question we can propose the following equation:

$d=750 -x(67)$