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3 years ago

Find the value of x and y

Mathematics

1 answer:

algol133 years ago

8 0

What do we know about these angles? Immediately, you might notice that (4y-8)° and (16x-4)° share a line. The same is true of (16x-4)° and (14x+4)°. Any straight line forms what's called a straight angle, which measures 180°, so we know that, since they add up to form a straight angle, (14x+4)° and (16x-4)° must add up to 180°. We can use that fact to set up an equation to solve for x:

(14x+4)+(16x-4)=180

After you solve for x, you should look to solve for y. How can we figure out what y is? If you're familiar with the vertical angle theorem, you'll know that all vertical angles (angles that are directly across from each other diagonally) are equal. So we know that 14x+4=4y-8. You can use the value of x you solved for before to solve this one fairly easily, and then you'll have both values.

You might be interested in

Simplify this rational expression. 2x^2+5x+3/2x^2-x-3

Murljashka [212]

Answer:

$2x+3$ / $2x-3$

Step-by-step explanation:

firstly we make two steps to simplify this question.

1st step: simplify $2x^{2} +5x+3$

to simplify this we use factorization

$2x^{2} +2x+3x+3$

$2x(x+1) +3(x+1)$

$(2x+3) (x+1)$ .....(1)

2nd step:simplify $2x^{2} -x-3$

$2x^{2} +2x-3x-3$

$2x(x+1)-3(x+1)$

$(2x-3)(x+1)$ .....(2)

now dividing (1) and (2), we get the answer

$2x+3/2x-3$

5 0

3 years ago

Evaluate 8.3p+7.9r when p =3 and r=4. 8.3( ) +7.9( ) = +31.6 help!!!!!

Alexandra [31]

Steps: 8.3(3) + 7.9(4) = 31.6

5 0

2 years ago

Read 2 more answers

I need someone to answer this question

SIZIF [17.4K]

4 over 3.2 = 6 over 4.8
I hope this helps!!

6 0

3 years ago

Can someone explain this differentiation question to me? I can differentiate but then I'm not sure what I am doing

weeeeeb [17]

note that gradient = $\frac{dy}{dx}$ at x = a

calculate $\frac{dy}{dx}$ for each pair of functions and compare gradient

(a)

$\frac{dy}{dx}$ = 2x and $\frac{dy}{dx}$ = - 1

at x = 4 : gradient = 8 and - 1 : 8 > - 1

(b)

$\frac{dy}{dx}$ = 2x + 3 and $\frac{dy}{dx}$ = - 2

at x = 2 : gradient = 7 and - 2 and 7 > - 2

(c)

$\frac{dy}{dx}$ = 4x + 13 and $\frac{dy}{dx}$ = 2

at x = - 7 : gradient = - 15 and 2 and 2 > - 15

(d)

$\frac{dy}{dx}$ = 6x - 5 and $\frac{dy}{dx}$ = 2x - 2

at x = - 1 : gradient = - 11 and - 4 and - 4 > - 11

(e)

y = √x = $x^{\frac{1}{2} }$

$\frac{dy}{dx}$ = 1/(2√x) and $\frac{dy}{dx}$ = 2

at x = 9 : gradient = $\frac{1}{6}$ and 2 and 2 > $\frac{1}{6}$

4 0

3 years ago

How do i find the slope

Elodia [21]

Hi, I'm happy to help!

To find the slope, you need to use the slope formula, where m is the slope:

m= $\frac{y_{2}-y_{1 } }{x_{2} -x_{1} }$

Slope means rise over run, or how much the line rises per the amount the line moves forward. This equation shows the movement from the y points to show rise, over the difference in the x points to show run.

Now, to find the slope we insert our values, starting with our second y point:

m= $\frac{2-y_{1 } }{x_{2} -x_{1} }$

Now insert our first y point:

m= $\frac{2-4 }{x_{2} -x_{1} }$

Now we insert our second x point:

m= $\frac{2-4 }{-3 -x_{1} }$

And finally our first x point:

m= $\frac{2-4 }{-3 -3 }$

Now, we solve:

m= $\frac{-2 }{-6}$

So, our slope is -2/-6, to simplify it, we remove both negatives because they cancel each other out.

m= $\frac{2 }{6}$

Now, we simplify our fraction by dividing the top and bottom by 2:

m= $\frac{1}{3}$

So, our slope is 1/3. This means that for every 1 unit the line rises, it goes to the right 3 units. The y-intercept is where the line hits the y axis.

If the question is asking for slope intercept form for the equation, you use y=mx+b

y represents any y coordinate on your line, m represents your slope (1/3), x represents any x coordinate on your line, and b represents your y-intercept (3).

If you were to insert these values, you would get:

y= $\frac{1}{3}$ x+3

You use this to find what a y coordinate would be so you can draw your line.

For the next equation we do the same thing:

m= $\frac{y_{2}-y_{1 } }{x_{2} -x_{1} }$

Insert our values:

m= $\frac{4-1}{2-(-4)}$

Get rid of the double negative:

m= $\frac{4-1}{2+4}$

Solve:

m= $\frac{3}{6}$

Simplify:

m= $\frac{1}{2}$

Now that we know our slope, let's plug it in to our slope intercept form equation.

y= $\frac{1}{2}$ x+3

I hope this was helpful! Keep learning! :D

5 0

3 years ago