65% of 89
65/100 = .65
.65 * 89 = 57.85
Answer: 57.85
Answer:
P [ K > 3.95] = 0.5633
Step-by-step explanation:
The interpretation of the given question goes thus;
Suppose that K is a random variable
P[-3.95 ≤ K ≤ 3.95] = 0.725
where; P [ + 3.95 < K ] = P [K < - 3.95]
P[K< 3.95] - P [K > - 3.95] =0.725
P [K < 3.95] - [ 1- P[K < 3.95]] = 0.725
P[k < 3.95] - 1 + P [ K < 3.95] = 0.725
3.95 P [ K < 3.95] -1 = 0.725
3.95 P [ K < 3.95] = 1.725
P [ K < 3.95] = 1.725/3.95
P [ K < 3.95] = 0.4367
P [ K > 3.95] = 1 - P[K< 3.95]
P [ K > 3.95] = 1 - 0.4367
P [ K > 3.95] = 0.5633
The variation equation is p = kr^2
<h3>How to determine the variation equation?</h3>
The variables are give as:
Pressure = P
Radius= r
The direct variation from p to the square of r is represented as:

Express as an equation
p = kr^2
Where k represents the constant of variation
Hence, the variation equation is p = kr^2
Read more about variation at:
brainly.com/question/6499629
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Answer:
first option
Step-by-step explanation:
Given
(3x² + 2x - 3)(x - 1)
Each term in the second factor is multiplied by each term in the first factor, that is
3x²(x - 1) + 2x(x - 1) - 3(x - 1) ← distribute parenthesis
= 3x³ - 3x² + 2x² - 2x - 3x + 3 ← collect like terms
= 3x³ - x² - 5x + 3
A dilation is a transformation, with center O and a scale factor of k
that is not zero, that maps O to itself and any other point P to P'.
The center O is a fixed point, P' is the image of P, points O, P and P'
are on the same line.
Thus, a dilation with centre O and a scale factor of

maps the original figure to the image in such a way that the
distances from O to the vertices of the image are

times the distances
from O to the original figure. Also the size of the image are <span>

times the
size of the original figure. Also the two resulting figures (i.e. the image and the pre-image are congruent)
Thus in the dilation of triangle DEF, the following are true.</span>
<span>∠F corresponds to ∠F'.
The measure of ∠E' is the measure of ∠E.
△DEF ≈ △D'E'F'</span>