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Reil [10]
3 years ago
15

Help 50 points and brainleist

Mathematics
2 answers:
ratelena [41]3 years ago
6 0

Answer:

hmmm it looks familiar to me

BaLLatris [955]3 years ago
5 0

Answer:

-0.5°C every hour

Step-by-step explanation:as the temperature of the bottom of the mountain changed at 1/5 the rate of temperatures change on the top of the mountain, so, the hourly rate of temperature change at the bottom of the mountain is=

-2.5×(1/5)

=-0.5

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In the figure below, angle y and angle x form vertical angles. Angle x forms a straight line with the 50° angle and the 40° angl
Musya8 [376]

Answer:

angle Y = 90 degrees

Step-by-step explanation:

Since it is stated that angle x forms a straight line with the 50 and 50 degree angles, and that angle x is vertical to angle y, we can do 40+50+y=180 to find angle Y.

8 0
3 years ago
Math question help me
JulsSmile [24]

Answer:

3 grams

Step-by-step explanation:

on the left side there is 3 circles and every circle is 3 grams, so there is 9 grams plus 6 squares for 2 grams its 12 . 9+12 =21 and two triangles with x mass

on the right side there is 2 circles , 2×3 = 6, and 3 squares, 3×2 = 6. 6+6=12 +5x

both sides are equal so we have

21+2x=12+5x

21-12=5x-2x

9=3x

x=3

6 0
3 years ago
Find sin θ, cot θ, and csc θ, where θ is the angle shown in the figure.
Natalka [10]

Step-by-step explanation:

everything can be found in the picture

8 0
3 years ago
A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears
marta [7]

Answer:

(a) The probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b) <em>n</em> = 28.09

Step-by-step explanation:

The random variable <em>Y</em>ₙ is defined as the total numbers of dollars paid in <em>n</em> years.

It is provided that <em>Y</em>ₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

The mean and standard deviation of <em>Y</em>ₙ are:

\mu_{Y_{n}}=40n\\\sigma_{Y_{n}}=\sqrt{100n}

(a)

For <em>n</em> = 20 the mean and standard deviation of <em>Y</em>₂₀ are:

\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\

Compute the probability that <em>Y</em>₂₀ exceeds 1000 as follows:

P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z>  4.47)\\=1-P(Z

**Use a <em>z </em>table for probability.

Thus, the probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b)

It is provided that P (<em>Y</em>ₙ > 1000) > 0.99.

P(Y_{n}>1000)=0.99\\1-P(Y_{n}

The value of <em>z</em> for which P (Z < z) = 0.01 is 2.33.

Compute the value of <em>n</em> as follows:

z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n}  \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0

The last equation is a quadratic equation.

The roots of a quadratic equation are:

n=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}

a = 16

b = -805.4289

c = 10000

On solving the last equation the value of <em>n</em> = 28.09.

8 0
3 years ago
3) Veronica traveled 126 miles on 3 gallons of gas. On another trip she traveled 210 miles on 5 gallons of gas. Find the unit ra
Goshia [24]
The answer is 42 mpg, all you need to do is divide 126/3 or 210/5 and they both equal 42.
8 0
4 years ago
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