All categories

3 years ago

75 miles to 225 miles as a fraction in simplest form

Mathematics

1 answer:

Pie3 years ago

5 0

Answer:

$\frac{1}{3}$

Step-by-step explanation:

When reducing a number to its lowest term you use the GCF of the denominator and numerator then divide using this number. :

$\frac{75}{225}$ ÷ $\frac{75}{75}$ = $\frac{1}{3}$

The gcf of 75 and 225 is 75 so we divide both the numerator and denominator by 75.

HOPE THIS HELPED

You might be interested in

All of the following are equivalent to 2(2a + b) + 8, except _____.

fiasKO [112]

Answer: 4(a + b + 2)

Step-by-step explanation: 2(2a + b) 8 equals 4a + 2b + 8. 4(a + b + 2) equals 4a + 4b + 8

3 0

3 years ago

Read 2 more answers

The gear is one of the oldest mechanical devices. It has been used since ancient times for its ability to increase or decrease r

eduard

The large gear attached to the pedals connected to the smaller gear

attached to the wheel allows the bicycle to travel further per rotation.

Correct responses:

Part A: Approximately 10.47 inches

Part B: 300°The d

Part C: Approximately 125.66 inches

Part D: The distance traveled increases by approximately 62.83 inches

<h3 /><h3>Methods used to calculate the above values</h3>

Given:

The radius of the large central gear, <em>r</em> = 4 inches

Radius of the small gear = 2 inches

Part A:

The distance travelled by the larger gear when the angle of rotation is 150° is given as follows;

$\displaystyle Distance \ travelled \ by \ larger \ gear = \mathbf{\frac{150^{\circ}}{360^{\circ}} \times 2 \times \pi \times 4 \, inches} = \frac{10}{3} \cdot \pi \ inches$

$\displaystyle Distance \ traveled \ by \ the \ outer \ edge = \frac{10}{3} \cdot \pi \ inches \approx \underline{ 10.47 \ inches}$

Part B:

When the small gear travels the same linear distance as the large gear in part A, we have;

$\displaystyle Degree \ of \ rotation = \frac{\frac{10}{3} \cdot \pi }{2 \times \pi \times 2 } \times 360^{\circ}= 300^{\circ}$

The degree of rotation of the small gear = <u>300°</u>

Part C:

The distance travelled, <em>C</em>, by a single rotation of the large gear is given as follows;

C = 2 × π × 4 inches = 8·π inches

The degree of rotation of the smaller gear following one rotation of the large gear is therefore;

$Degree \ of \ rotation = \displaystyle \frac{8\cdot \pi \ inches}{4 \cdot \pi \ inches } \times 360^{\circ} = \mathbf{ 720^{\circ}}$

720° = 2 × 360°

1 complete rotation is equivalent to 360°.

Therefore'

720° is equivalent to two complete rotation.

Therefore, the smaller gear and the wheel rotates twice for each rotation of the large gear

The distance the bicycle travels = 2 × The circumference of the wheel

Therefore;

Distance traveled by the bicycle = 2 × 2 × π × 10 inches = 40·π inches

Distance traveled by the bicycle = 40·π inches ≈ <u>125.66 inches</u>

Part D:

If the radius of the small gear is 1.5 inches and the radius of the large gear is 4.5 inches, we have;

Number of rotation of the small gear for each rotation of the large gear = 3 rotations

Therefore, number of rotation of the wheel = 3

Distance the bicycle travels = 3 × 2 × π × 10 inches = 60·π inches

The difference in distance traveled = 60·π inches - 40·π inches = 20·π inches

The distance traveled by the bicycle increases by 20·π inches ≈ <u>62.83 inches</u>

Learn more about gear transmission here:

brainly.com/question/14646065

brainly.com/question/3926797

8 0

3 years ago

What is the reciprocal of each number?

Usimov [2.4K]

A
2/9=9/2
-9/2=-2/9
9/2=2/9
-2/9=-9/2

7 0

4 years ago

Read 2 more answers

Abcd is a rectangle. Find the length of each diagonal. .AC= 3y/5 BD=3y-4

-Dominant- [34]

I hope this helps you

3 0

3 years ago

Read 2 more answers

Multiply and simplify. 6xy^3z⋅3x^2yx^2

klio [65]

It's letter c

multiply the coefficient then just add the degrees of each letter

4 0

3 years ago