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Illusion [34]
3 years ago
12

Find the equation of the line that is perpendicular to y=-1/5x-3 and contains the point (1,2).

Mathematics
1 answer:
Nat2105 [25]3 years ago
5 0
For perpendicular the way you find it is by flipping the fraction. and adding a negative. remember that whole number are fractions divided by 1.

so what you would get is

y=5x+a

then we put in the points into our x and y.

2=5(1)+a
now solve

2-5=a

a=-3

Now you will put into standard form

y=5x-3


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Answer:

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Step-by-step explanation:

Given

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Required

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- Determine the equation to model the data

To check for type of variation; we'll make use of trial by error method.

To start with; We'll check for direct variation.

This is done using the following expression;

Y = kXwhere k is the constant of variation

Make k the subject of formula

k = \frac{Y}{X}

When Y = 6, X= 2

K = \frac{6}{2} = 3

When Y = 3, X = 4

K = \frac{3}{4}

There's no need to check further as both values of k are not equal

To check for inverse variation;

Y = \frac{k}{X}

Make k the subject of formula

k = YX

When Y = 6, X= 2

K = 6 * 2 = 12

When Y = 3, X = 4

K = 3 * 4 = 12

When Y = 3/2; X = 8

K = \frac{3}{2} * 8 = \frac{24}{2} = 12

When Y = 1, X = 12

K = !2 * 1 = 12

Note that for all values of X and Y, K remains constant;

Hence, the table represents an inverse direction

To determine the equation;

We make use of  k = YX

Substitute 12 for k

So, the equation becomes

12 = XY

Reorder

XY = 12

Hence, the equation is XY = 12

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