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valentinak56 [21]
3 years ago
7

Pedro's Diner is open six days a week. His income for the first five days this week was

Mathematics
1 answer:
S_A_V [24]3 years ago
6 0

Answer:

$330

Step-by-step explanation:

What is mean/average?

It is the "sum of all the numbers" divided by the "number of numbers".

An average of 200 for 6 numbers means:

Average=\frac{SUM}{NumberOfNumbers}\\200=\frac{SUM}{6}\\SUM=200*6\\SUM=1200

THus, if we were to add the 6 numbers, we would get "1200". Let the 6th number be x, so we can write:

120 + 110 + 200 + 300 + 140 + x = 1200

870 + x = 1200

x = 1200 - 870

x = 330

To make the average $200, Pedro needs to make $330 on 6th day.

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natta225 [31]

Answer:

755757

Step-by-step explanation:

6 0
3 years ago
Can someone please help mee i need the exact answer(30 points will give brainliest!!!)
Bas_tet [7]

The domain of the given graph is [−3, ∞) and the range is (−∞, 4].

We need to find the domain and range of the given graph.

<h3>What are the domain and range of the function?</h3>

The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values that it can take.

We can observe that the graph extends horizontally from −3 to the right without a bound, so the domain is [−3, ∞). The vertical extent of the graph is all range values 4 and below, so the range is (−∞, 4].

Therefore, the domain of the given graph is [−3, ∞) and the range is (−∞, 4].

To learn more about domain and range visit:

brainly.com/question/1632425.

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6 0
2 years ago
For any linear function f(x) = mx + b, when does 5f(x) = f(5x)?
S_A_V [24]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
Ignoring leap days, the days of the year can be numbered 1 to 365. Assume that birthdays are equally likely to fall on any day o
faust18 [17]

Answer:

Follows are the solution to the given question:

Step-by-step explanation:

They can count the days of the year 1 to 365. The random project consists of drawing a sample of n objects from D where elements are n people's birth in a group but instead, D = {1,....365}. And then there's the issue.

S=365^n

This because the list of future birthdays of n people was its test point; therefore m points will be in the sequence so each point contains 365 distinct outcomes. The probability function P for \Omega is that any event is likely to happen in 365 days.

P(x)=\frac{1}{365^{n}}

if x is between 1 and 365 as well as the occurrence is just all similarly possible

In point i:

That somebody mentions their birthday throughout the party

Guess I was born on day b. Therefore the consequence of "x is in A" is "b is now in the series of x," which is to say, b = bk for some amount k approximately 1 and n.

In point ii:

Any 2 persons share the same birthday at this party". A result x is in B" means which "two of entries in x are same." This means that perhaps the outcome x is in B if or only if bj = bk is in B of two numbers j, and k of 1, of two. , no, n.

In point iii:

Many three students share the same birthday with both the party. The consequence is x at the level of C only when bj = bk = bl at three (different) indices, j, k, l, 1. , no, n.

6 0
3 years ago
CAN ANYONE PLEASE HELP ME ON THIS!!
GarryVolchara [31]

Answer:

8. b

9.C

10.a

11.a

12. c

13. b

brainliest pls <3

7 0
3 years ago
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