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Anettt [7]
3 years ago
9

Rachel Perez rented a car for 3 days at $40.00 per day, plus $0.20 per mile. To protect herself in case of an accident, she purc

hased the collision deductible for $10.00 per day and paid $40.00 for gasoline to cover the 500 miles she drove. What was her total cost to rent the car?
Mathematics
1 answer:
expeople1 [14]3 years ago
8 0

Answer:

$290.

Step-by-step explanation:

We have been given that Rachel Perez rented a car for 3 days at $40.00 per day.

\text{The cost of renting a car for 3 days}=3\times \$40

\text{The cost of renting a car for 3 days}=\$120

We are also told that she pays $0.20 per mile for renting the car. As she covered a total distance of 500 miles, so cost of renting car foe 500 miles will be:

\text{Cost of renting the car for 500 miles}=500\times \$0.20

\text{Cost of renting the car for 500 miles}=\$100

As Rachel purchased the collision deductible for $10.00 per day to protect herself in case of an accident, so cost of collision deductible for 3 days will be:

\text{The cost of collision deductible for 3 days}=3\times \$10

\text{The cost of collision deductible for 3 days}=\$30

She also paid $40 for gasoline to cover 500 miles, so we can find total cost to rent the car for 3 days to cover 500 miles by adding all the expenses.

\text{The total cost to rent the car}=\$120+\$100+\$30+\$40

\text{The total cost to rent the car}=\$290

Therefore, the total cost to rent the car was $290.

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Answer:

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Step-by-step explanation:

Given

See attachment for grid

Required

The transformation from the current location to the new location

To do this, we pick two corresponding points on the current location and the new location.

We have:

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The rule to this is:

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Step2: Y2-Y1 over X2-X1

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